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postnew [5]
3 years ago
14

The Earth completes one revolution around the sun, and its average distance from to the sun during one revolution is 94.4 millio

n miles. Assuming that Earth's orbit is a perfect circle with the sun at its center, calculate the magnitude of the Earth's average velocity (in m/s) over a period of one year.
Physics
1 answer:
olga nikolaevna [1]3 years ago
5 0

Answer:

4817 m/s

Explanation:

Velocity is the time rate of change of displacement. The S.I unit of velocity is m/s. Velocity is the ratio of displacement to time, it is given by the formula:

Velocity  = displacement / time

Average velocity is the ratio of the total distance travelled to the total time taken. It is given by the formula:

Average velocity = total distance travelled / total time taken

Given that the one revolution = 94.4 million miles, time taken = 1 year, hence:

1 mile = 1609.34 m

94.4 million miles = 94.4 *10^6\  miles*\frac{1609.34\ m}{1\ mile} =1.5*10^{11}\ m

1 year = 31536000 s

Therefore:

Average velocity = total distance travelled / total time taken

Average velocity = 1.5 * 10¹¹ m / 31536000 = 4817 m/s

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a bullet is fired upwards with the initial velocity of 250m/s. determine the time taken to reach the maximum height
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I would like to know why this is the correct answer
kati45 [8]

Answer:

The correct answer is the ratio of net force to mass is constant across all objects.

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3 years ago
38.4 mol of krypton is in a rigid box of volume 64 cm^3 and is initially at temperature 512.88°C. The gas then undergoes isobari
kolbaska11 [484]

Answer:

Final volumen first process V_{2} = 98,44 cm^{3}

Final Pressure second process P_{3} = 1,317 * 10^{10} Pa

Explanation:

Using the Ideal Gases Law yoy have for pressure:

P_{1} = \frac{n_{1} R T_{1} }{V_{1} }

where:

P is the pressure, in Pa

n is the nuber of moles of gas

R is the universal gas constant: 8,314 J/mol K

T is the temperature in Kelvin

V is the volumen in cubic meters

Given that the amount of material is constant in the process:

n_{1} = n_{2} = n

In an isobaric process the pressure is constant so:

P_{1} = P_{2}

\frac{n R T_{1} }{V_{1} } = \frac{n R T_{2} }{V_{2} }

\frac{T_{1} }{V_{1} } = \frac{T_{2} }{V_{2} }

V_{2} = \frac{T_{2} V_{1} }{T_{1} }

Replacing : T_{1} =786 K, T_{2} =1209 K, V_{1} = 64 cm^{3}

V_{2} = 98,44 cm^{3}

Replacing on the ideal gases formula the pressure at this piont is:

P_{2} = 3,92 * 10^{9} Pa

For Temperature the ideal gases formula is:

T = \frac{P V }{n R }

For the second process you have that T_{2} = T_{3}  So:

\frac{P_{2} V_{2} }{n R } = \frac{P_{3} V_{3} }{n R }

P_{2} V_{2}  = P_{3} V_{3}

P_{3} = \frac{P_{2} V_{2}}{V_{3}}

P_{3} = 1,317 * 10^{10} Pa

7 0
3 years ago
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