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postnew [5]
3 years ago
14

The Earth completes one revolution around the sun, and its average distance from to the sun during one revolution is 94.4 millio

n miles. Assuming that Earth's orbit is a perfect circle with the sun at its center, calculate the magnitude of the Earth's average velocity (in m/s) over a period of one year.
Physics
1 answer:
olga nikolaevna [1]3 years ago
5 0

Answer:

4817 m/s

Explanation:

Velocity is the time rate of change of displacement. The S.I unit of velocity is m/s. Velocity is the ratio of displacement to time, it is given by the formula:

Velocity  = displacement / time

Average velocity is the ratio of the total distance travelled to the total time taken. It is given by the formula:

Average velocity = total distance travelled / total time taken

Given that the one revolution = 94.4 million miles, time taken = 1 year, hence:

1 mile = 1609.34 m

94.4 million miles = 94.4 *10^6\  miles*\frac{1609.34\ m}{1\ mile} =1.5*10^{11}\ m

1 year = 31536000 s

Therefore:

Average velocity = total distance travelled / total time taken

Average velocity = 1.5 * 10¹¹ m / 31536000 = 4817 m/s

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alexandr1967 [171]

Answer:

v=\sqrt{k\frac{e^2}{m_e r}}, 2.18\cdot 10^6 m/s

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k\frac{(e)(e)}{r^2}=m_e \frac{v^2}{r}

where

k is the Coulomb constant

e is the magnitude of the charge of the electron

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Solving for v, we find

v=\sqrt{k\frac{e^2}{m_e r}}

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m_e = 9.11\cdot 10^{-31}kg

and the charge is

e=1.6\cdot 10^{-19} C

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v=\sqrt{(9\cdot 10^9 m/s) \frac{(1.6\cdot 10^{-19} C)^2}{(9.11\cdot 10^{-31} kg)(5.3\cdot 10^{-11} m)}}=2.18\cdot 10^6 m/s

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4 years ago
4. A 62.0-kg person, standing on the diving board, dives straight down into the water. Just before striking the water, her speed
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To solve this problem it is necessary to apply the concepts related to the Moment. The moment in terms of the Force and the time can be expressed as

\Delta P = F\Delta t

F = Force

\Delta t = Time

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\Delta v = Change in velocity

Our values are given as

\Delta t=1.65s

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