width= 8
Length= 15
(8x15= 120 and 8 is 7 less than 15)
In a quadratic equation
q(x) = ax^2 + bx + c
The discriminant is = b^2 - 4ac
We have that discriminant = 3
If
b^2 - 4ac > 0, then the roots are real.
If
b^2 - 4ac < 0 then the roots are imaginary
<span>In
this problem b^2 - 4ac > 0 3 > 0 </span>
then
the two roots must be real
Answer:
2(a+2b+15)
Step-by-step explanation:
hope this helps!
Given:
The quadratic equation is

To find:
The vertex of the given quadratic equation.
Solution:
If a quadratic function is
, then

We have,

It can be written as

...(i)
Here,
.



Putting
in (i), we get
On further simplification, we get
So, the vertex of the given quadratic equation is
.
Therefore, the correct option is A.