3 years ago

Please help me graph this and I will thank you

Mathematics

1 answer:

rusak2 [61]3 years ago

3 0

Draw the bar above the 6 and make it go up to 300 :)

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In his boat, Sheldon can travel 45 mi downstream in the same time that it takes to travel 9 mi upstream. If the rate of the curr

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Answer:

9 mph

Step-by-step explanation:

-let x be the speed of current and t be time. The speed equation for both directions can then be represented as:

$Speed=\frac{Distance}{Time}\\\\\#Upstream\\(u-6)t=9\\\\\#Donwstream\\\\(u+6)t=45$

#Since t is equal in both, we can do away with t.

#We the divide the downstream equation by the upstream equation as:

$\frac{u+6}{u-6}=\frac{45}{9}\\\\(u+6)=5(u-6)\\\\u+6=5u-30\\\\4u=36\\\\u=9$

Hence, the boat's speed in still water is 9 mph

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2 years ago

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Step-by-step explanation:

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What is solution to this system of equations? x + 4y = 12 and x = 0<br>PLSSS hurry

Margaret [11]

Answer:

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Step-by-step explanation:

If x=0, then we can just plug that value into the other equation and solve for y:

x+4y=12

0+4y=12

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