To solve this, you have to know that the first derivative of a function is its slope. When an interval is increasing, it has a positive slope. Thus, we are trying to solve for when the first derivative of a function is positive/negative.
f(x)=2x^3+6x^2-18x+2
f'(x)=6x^2+12x-18
f'(x)=6(x^2+2x-3)
f'(x)=6(x+3)(x-1)
So the zeroes of f'(x) are at x=1, x=-3
Because there is no multiplicity, when the function passes a zero, he y value is changing signs.
Since f'(0)=-18, intervals -3<x<1 is decreasing(because -3<0<1)
Thus, every other portion of the graph is increasing.
Therefore, you get:
Increasing: (negative infinite, -3), (1, infinite)
Decreasing:(-3,1)
If one square is divided into 9 smaller equal squares, then they have to be arranged in 3 lines of 3, that is 3 smaller equal squares per side of the original big square. That said, the area of the big square is equal to the multiplication of 3 small squares sides times 3 small squares sides, call x the length of the small squares.
So,
area = 9 = 3x*3x
9x^2 = 9
x^2 = 1
x = 1
therefore the smaller squares have sides of 1 unit
Answer:
RQ = 18
Step-by-step explanation:
KR is an angle bisector and divides the opposite side into segments that are proportional to the other two sides, that is
= 
, substitute values
= 
( cross- multiply )
45(38 - x) = 50x ← distribute left side
1710 - 45x = 50x ( add 45x to both sides )
1710 = 95x ( divide both sides by 95 )
18 = x
That is RQ = 18
OK...... your answer would be
- 10y^2 - 26y + 1/y
H0P3 It H3LPS :)
Answer:
22.25
Step-by-step explanation:
1302-1124/2016-2008
