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Vikki [24]
3 years ago
10

What is the cube root of 8​

Mathematics
1 answer:
alina1380 [7]3 years ago
6 0

Answer:

its 2

Step-by-step explanation:

because 2*2*2 is 8

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diamong [38]

Answer:

b

Step-by-step explanation:

5 0
3 years ago
Help me out please and thanks
omeli [17]

Answer:

Step-by-step explanation:

If you are trying to <u>solve the system of equations</u> then its

(x,y)=(-1,2)

If you are trying to <u>rewrite the system of equations</u> then its

x+6y=11

x-2y=-5

3 0
2 years ago
Which number is irrational <br> 25/9
pantera1 [17]
We have a fraction of two integers, so 25/9 is rational. A rational number is any fraction of two integers (as long as the denominator is not zero).
5 0
3 years ago
En un pozo petrolìfero produce cada dia 2680 barriles de petroleo. Si cada barril contiene 159 litros de petroleo, cuantos litro
Aliun [14]

Answer:

426,120 litros se producen en un día Se producen

12,783,600 litros por mes (para un cálculo de 30 días en un mes)

Step-by-step explanation:

Aquí, debemos calcular la cantidad en litros de petróleo producido en un pozo petrolero.

Se nos dice que se producen 2.680 barriles por día y cada barril contiene 159 litros de petróleo.

La producción diaria en litros es, por lo tanto, de 159 * 2680 = 426,120 litros.

Ahora, para la producción mensual, supongamos que hay 30 días en un mes, la cantidad en litros producidos por mes sería la cantidad diaria multiplicada por la cantidad de días en un mes.

Matemáticamente, eso sería 30 * 426,120 = 12,783,600 litros

4 0
3 years ago
<img src="https://tex.z-dn.net/?f=%20-%203%20%2B%205i%20%20%5Cdiv%20%20-%203%20-%204i" id="TexFormula1" title=" - 3 + 5i \div
Likurg_2 [28]

Answer:

\frac{-11}{25}+\frac{-27}{25}i given you are asked to simplify

\frac{-3+5i}{-3-4i}

Step-by-step explanation:

You have to multiply the numerator and denominator by the denominator's conjugate.

The conjugate of a+bi is a-bi.

When you multiply conjugates, you just have to multiply first and last.

(a+bi)(a-bi)

a^2-abi+abi-b^2i^2

a^2+0         -b^2(-1)

a^2+-b^2(-1)

a^2+b^2

See no need to use the whole foil method; the middle terms cancel.

So we are multiplying top and bottom of your fraction by (-3+4i):

\frac{-3+5i}{-3-4i} \cdot \frac{-3+4i}{-3+4i}=\frac{(-3+5i)(-3-4i)}{(-3-4i)(-3+4i)}

So you will have to use the complete foil method for the numerator. Let's do that:

(-3+5i)(-3+4i)

First: (-3)(-3)=9

Outer::  (-3)(4i)=-12i

Inner: (5i)(-3)=-15i

Last: (5i)(4i)=20i^2=20(-1)=-20

--------------------------------------------Combine like terms:

9-20-12i-15i

Simplify:

-11-27i

Now the bottom (-3-4i)(-3+4i):

F(OI)L (we are skipping OI)

First:-3(-3)=9

Last: -4i(4i)=-16i^2=-16(-1)=16

---------------------------------------------Combine like terms:

9+16=25

So our answer is \frac{-11-27i}{25}{/tex] unless you want to seprate the fraction too:[tex]\frac{-11}{25}+\frac{-27}{25}i

6 0
3 years ago
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