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3 years ago

Ken borrowed $ 2000 from Sam at 8% per year.what is the simple interest after 6 years? A.$ 160 B.$ 960 C. $ 1,600 D. $ 9,600

Mathematics

1 answer:

Klio2033 [76]3 years ago

7 0

Step-by-step explanation:

2000×8/100=160

160×6=960

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Do the organic prices vary directly with the conventional prices? If so, identify k. Does the total cost of organic apples vary

wlad13 [49]

Answer:

1: No, this is not direct variation

2: Yes, this is direct variation with k= 2.34

Step-by-step explanation:

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2 years ago

If 2x - 3y = 24 and 3x + 4y = 2, what is the value of x - y ?

Reika [66]

Answer:

Step-by-step explanation:

2x - 3y = 24 ------ (1)

3x + 4y = 2 ------ (2)

(1) × 4,

8x - 12y = 96 ------ (3)

(2) × 3,

9x + 12y = 6 ------ (4)

(3) + (4)

17x = 96 + 6

= 102

x = 102 ÷ 17

= 6

Sub x = 6 into (2),

3(6) + 4y = 2

18 + 4y = 2

4y = 2 - 18

= -16

y = -16 ÷ 4

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Therefore,

x - y = 6 - (-4)

= 6 + 4

= 10

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2 years ago

6-a/a+5 =

Anni [7]

d) (6-a) divide (a+5)

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3 years ago

A tank has the shape of a surface generated by revolving the parabolic segment y = x2 for 0 ≤ x ≤ 3 about the y-axis (measuremen

Darina [25.2K]

Answer:

$100\pi\int\limits^9_0 {(\sqrt y)^2(14-y)} \, dy$ ft-lbs.

Step-by-step explanation:

Given:

The shape of the tank is obtained by revolving $y=x^2$ about y axis in the interval $0\leq x\leq 3$ .

Density of the fluid in the tank, $D=100\ lbs/ft^3$

Let the initial height of the fluid be 'y' feet from the bottom.

The bottom of the tank is, $y(0)=0^2=0$

Now, the height has to be raised to a height 5 feet above the top of the tank.

The height of top of the tank is obtained by plugging in $x=3$ in the parabolic equation . This gives,

$H=3^2=9\ ft$

So, the height of top of tank is, $y(3)=H=9\ ft$

Now, 5 ft above 'H' means $H+5=9+5=14$

Therefore, the increase in height of the top surface of the fluid in the tank is given as:

$\Delta y=(14-y)$ ft

Now, area of cross section of the tank is given as:

$A(y)=\pi r^2\\r\to radius\ of\ the\ cross\ section$

Radius is the distance of a point on the parabola from the y axis. This is nothing but the x-coordinate of the point.

We have, $y=x^2$

So, $x=\sqrt y$

Therefore, radius, $r=\sqrt y$

Now, area of cross section is, $A(y)=\pi (\sqrt y)^2$

Work done in pumping the contents to 5 feet above is given as:

$W=D\int\limits^{y(3)}_{y(0)} {A(y)(\Delta y)} \, dy$

Plug in all the values. This gives,

$W=100\int\limits^9_0 {\pi (\sqrt y)^2(14-y)} \, dy\\\\W=100\pi\int\limits^9_0 { (\sqrt y)^2(14-y)} \, dy\textrm{ ft-lbs}$

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3 years ago

Please help me with this answer, ASAP

Licemer1 [7]

Answer:

Perpendicular to the base

Step-by-step explanation:

The pyramid was sliced in half creating two halves. Since the cross section forms a perpendicular angle, the cut was perpendicular to the base of the solid.

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3 years ago