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arsen [322]
3 years ago
12

How are mixed numbers used in The real world

Mathematics
1 answer:
Jobisdone [24]3 years ago
3 0
Often, mixed number are used in terms of amounts of something. You would never say I have 16/5 pies. You would say I have 3 full pies and 1/5 of another pie. 

In this example, 3 1/5 is better to use than the improper 16/5

Hope this helps!
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PATS, PETE AND KOFFI ANNUAL SALARIES AGGREGATE TO 200,000.00 A YEAR PETE MAKES $11000.00 MORE THAN KOFFI AND PAT MAKES $1000.00
grandymaker [24]

Answer:

Koffi's monthly salary: $3500 ($42000 annually)

Pete's monthly salary: $4416.7 ($53000 annually)

Pat's monthly salary: $8750 ($105000 annually)

Step-by-step explanation:

Let x represent Pat's annual salary

Let y represent Pete's annual salary

Let z represent Koffi's annual salary

According to the question, their annual salaries sum up to$200000 i.e. x + y + z= $200000

Pete makes $11000 more than Koffi anually means that y = $11000 + z

Pat makes $1000 less than twice (×2) of Pete's annual salary i.e. x = 2y - $1000

Hence, we have 3 equations:

(1)..... x + y + z= $200000

(2).... y = $11000 + z

(3).... x = 2y - $1000

First, we substitute y into equation (3) i.e.

x = 2(11000 + z) - 1000

x = 22000 + 2z - 1000

x = 21000 + 2z............ (4)

We then insert equations (4) and (2) into equation (1) to get z:

x + y + z = 200000

21000 + 2z + 11000 + z + z = 200000

4z + 32000 = 200000

4z = 200000 - 32000

4z = 168000

z = 42000

Hence, z (Koffi's) annual salary is $42000.

To get y, we substitute z in equation (2).

y = 11000 + z

y = 11000 + 42000

y = 53000

Hence, y (Pete's) annual salary is $53000

To get x, we add $42000 with $53000, and subtract from $200000 i.e. 42000 + 53000 = 95000

200000 - 95000 = 105000

Hence, x (Pat's) annual salary is $105000.

In order to get the monthly salary of each individual, we divide their annual salary by 12:

Koffi (z) = 42000/12 = $3500

Pete (y) = 53000/12 = $4416.7

Pat (x) = 105000/12 = $8750

4 0
3 years ago
I've got two of these kinds of problems and no clue how to do them, help please!
Bogdan [553]
Hello,

3x^3+2x^2-3x-2=0\\

3x^3-3x+2x^2-2=0\\


3x(x^2-1)+2(x^2-1)=0\\

(x^2-1)(3x+2)=0\\

(x-1)(x+1)(3x+2)=0\\

Sol=\{- \dfrac{2}{3}, -1,1 \}

4 0
4 years ago
Read 2 more answers
How to solve this question
charle [14.2K]

7(x + 3 ) = 6 - (-7x - 15)

Apply the distributive rule to remove parentheses.

7x + 21 = 6 + 7x + 15

Right away, you should be able to see that 7x will be cancelled rendering this equation to have no solution.

Answer: NO SOLUTION

4 0
3 years ago
Read 2 more answers
Which number is the largest?<br> A. 20.999<br> B. 21.767<br> C. 21.76<br> D. 21.80<br> E. 21.798
Elza [17]

Answer:

21.80

Step-by-step explanation:

3 0
3 years ago
hey, do any of you guys know how to plot functions on a graph. You know like f(X) and g(X)? I find it really hard and also do yo
Tpy6a [65]
It helps if you have an example, like f(x) = 2x+3
What you typically do, is:

- draw xy axis, label them (ie., 1,2,3,4 along both axes)
- calculate the f(x) values for several x (e.g., -2, 0, 1, 3, doesn't matter).
- plot the calculated values as points. The calculated f(x) is your y value.
- sketch a smooth line through the points. It helps if you know in advance if the line is going to be straight or curved. 
- The more points you calculate, the more accurate your graph will be
3 0
3 years ago
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