Answer:
a.) Between 0.5 and 3 seconds.
Step-by-step explanation:
So I just went ahead and graphed this quadratic on Desmos so you could have an idea of what this looks like. A negative quadratic, and we're trying to find when the graph's y-values are greater than 26.
If you look at the graph, you can easily see that the quadratic crosses y = 26 at x-values 0.5 and 3. And, you can see that the quadratic's graph is actually above y = 26 between these two values, 0.5 and 3.
Because we know that the quadratic's graph models the projectile's motion, we can conclude that the projectile will also be above 26 feet between 0.5 and 3 seconds.
So, the answer is a.) between 0.5 and 3 seconds.
Answer:
(4,0,-5)
Step-by-step explanation:
Since we move 4 points along +ve x-axis so, x coordinate is 4
We did not move any point along y-axis so y coordinate is 0
we moved 5 points along -ve z-axis so z coordinate is -5
so our position is (x,y,z) = (4,0,-5)
X^2+x-12=0 factors out into (x+4)(x-3) so the answer is: x=-4, x=3
Order from least to greatest: 15,21,15,15,18,19,14,20,95,18,21,14,15,20,16,14,22,21,15,19
EleoNora [17]
1,2,14,14,14,15,15,15,15,15,16,18,18,19,19,20,20,21,21,22,95
Hope that helps!!!