All categories

3 years ago

Define the following terms: 1. Mean 2. Median 3. Mode 4. Range

Mathematics

1 answer:

Lyrx [107]3 years ago

7 0

Answer:

1. In mathematics and statistics, the arithmetic mean, or simply the mean or the average, is the sum of a collection of numbers divided by the count of numbers in the collection. The collection is often a set of results of an experiment or an observational study, or frequently a set of results from a survey.

2. In statistics and probability theory, a median is a value separating the higher half from the lower half of a data sample, a population, or a probability distribution. For a data set, it may be thought of as "the middle" value.

3. The mode is the value that appears most often in a set of data values. If X is a discrete random variable, the model is the value x at which the probability mass function takes its maximum value. In other words, it is the value that is most likely to be sampled.

4. the set of values that a given function can take as its argument varies.

You might be interested in

(x-5y,-3):(1,3y-x) find value of x and y<br>Please help me to solve thiss!!

11Alexandr11 [23.1K]

Answer:

x=11, y=2

Step-by-step explanation:

We can set 1 equal to x-5y and then solve for x. and y.

x = 5y+1

y = x-1/5

We can use this information and plug back in the values for 3y-x or x-5y.

We can set -3 = 3y-x or 1 = x-5y.

To solve for x using -3 = 3y-x we can swap the values of x and y which would make it -3 = 3(x-1/5)-5(x-1/5)+1.

We can do a bit of algebra which would get us x = 11.

Knowing that y = x-1/5 we can plug in 11 for x. y = 11-1/5.

y=2

x=11, y=2

3 0

1 year ago

Lagrange multipliers have a definite meaning in load balancing for electric network problems. Consider the generators that can o

Ivahew [28]

Answer:

The load balance $(x_1,x_2,x_3)=(545.5,272.7,181.8)$ Mw minimizes the total cost

Step-by-step explanation:

<u>Optimizing With Lagrange Multipliers</u>

When a multivariable function f is to be maximized or minimized, the Lagrange multipliers method is a pretty common and easy tool to apply when the restrictions are in the form of equalities.

Consider three generators that can output xi megawatts, with i ranging from 1 to 3. The set of unknown variables is x1, x2, x3.

The cost of each generator is given by the formula

$\displaystyle C_i=3x_i+\frac{i}{40}x_i^2$

It means the cost for each generator is expanded as

$\displaystyle C_1=3x_1+\frac{1}{40}x_1^2$

$\displaystyle C_2=3x_2+\frac{2}{40}x_2^2$

$\displaystyle C_3=3x_3+\frac{3}{40}x_3^2$

The total cost of production is

$\displaystyle C(x_1,x_2,x_3)=3x_1+\frac{1}{40}x_1^2+3x_2+\frac{2}{40}x_2^2+3x_3+\frac{3}{40}x_3^2$

Simplifying and rearranging, we have the objective function to minimize:

$\displaystyle C(x_1,x_2,x_3)=3(x_1+x_2+x_3)+\frac{1}{40}(x_1^2+2x_2^2+3x_3^2)$

The restriction can be modeled as a function g(x)=0:

$g: x_1+x_2+x_3=1000$

$g(x_1,x_2,x_3)= x_1+x_2+x_3-1000$

We now construct the auxiliary function

$f(x_1,x_2,x_3)=C(x_1,x_2,x_3)-\lambda g(x_1,x_2,x_3)$

$\displaystyle f(x_1,x_2,x_3)=3(x_1+x_2+x_3)+\frac{1}{40}(x_1^2+2x_2^2+3x_3^2)-\lambda (x_1+x_2+x_3-1000)$

We find all the partial derivatives of f and equate them to 0

$\displaystyle f_{x1}=3+\frac{2}{40}x_1-\lambda=0$

$\displaystyle f_{x2}=3+\frac{4}{40}x_2-\lambda=0$

$\displaystyle f_{x3}=3+\frac{6}{40}x_3-\lambda=0$

$f_\lambda=x_1+x_2+x_3-1000=0$

Solving for \lambda in the three first equations, we have

$\displaystyle \lambda=3+\frac{2}{40}x_1$

$\displaystyle \lambda=3+\frac{4}{40}x_2$

$\displaystyle \lambda=3+\frac{6}{40}x_3$

Equating them, we find:

$x_1=3x_3$

$\displaystyle x_2=\frac{3}{2}x_3$

Replacing into the restriction (or the fourth derivative)

$x_1+x_2+x_3-1000=0$

$\displaystyle 3x_3+\frac{3}{2}x_3+x_3-1000=0$

$\displaystyle \frac{11}{2}x_3=1000$

$x_3=181.8\ MW$

And also

$x_1=545.5\ MW$

$x_2=272.7\ MW$

The load balance $(x_1,x_2,x_3)=(545.5,272.7,181.8)$ Mw minimizes the total cost

5 0

3 years ago

A monster can eat 36 cookies in 9 minuets.How many cookies can the monster eat in 12 minuets?

Vaselesa [24]

a monster can eat 48 cookies in 12 minutes me thinks

5 0

3 years ago

finding the distance along a diagonal with the distance formula requires you evaluate a square root. true or false ?

bija089 [108]

Answer:

true

Step-by-step explanation:

Pythagoras is simply c² = a² + b².

so, it does not matter which side of the triangle we need, we will always have to solve a square root for the final result.

7 0

2 years ago

H(n) = n^3 - 2; Find h(3)

Snezhnost [94]

Answer:

Step-by-step explanation:

Easy! You plug in 3 for n! H(3) = 3^3 - 2

3^3 = 27 - 2 = 25

4 0

3 years ago