So area is length times width therefore
A=LW
44ft^2=5.5W
divide both sides by 5.5
44/5.5=Width=8 feet
Answer:
The player throws 127.3 ft from second base to home plate.
Step-by-step explanation:
Given:
Distance from home to first base = 90 ft
Distance from first base to second base = 90 ft
We need to find the distance from second base to home.
Solution:
Now we can assume the complete scenario to be formed as a right angled triangle with two sides given and to find the third side.
Now by using Pythagoras theorem which states that;
Square of the hypotenuse side is equal to sum of squares of other two sides.
framing in equation form we get;
distance from second base to home = 
Rounding to nearest tent we get;
distance from second base to home = 127.3 ft
Hence The player throws 127.3 ft from second base to home plate.
P = W/t
W = Fd
P = Fd/t = F/t d
Answer:
z=110
a=69
b=47
c=116
d=93
e=86
Step-by-step explanation: