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padilas [110]
3 years ago
7

1. Which is an example of chemical potential

Physics
2 answers:
kirill [66]3 years ago
7 0
D. burning fuel to move a car
balu736 [363]3 years ago
3 0

Answer:

D

Explanation:

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All objects _<br> energy.
Alekssandra [29.7K]

Answer:

Explanation:

All objects <u>radiate</u> energy.

8 0
3 years ago
How do you know whether to put a nine or a 10 in front of the number on the weather station
3241004551 [841]
If the air pressure on the station model is 500 or more, place a 9 in front of this number. If the pressure number on the station is less than 500 add a 10 in front of this number. 

Good luck :)
7 0
3 years ago
State the kinematic quantity that is equivalent to the slope of a position-time graph
Anni [7]

The figure shows the arrangement of given data.

The displacement is considered along X direction and time along Y direction.

The slope of the graph is given by tan θ

So tan θ = Δx/Δt = Velocity between those two points considered for finding slope of graph.

So slope of position time is graph is equivalent to kinematic quantity Velocity.

6 0
3 years ago
What is current and si unit<br>​
Art [367]

Answer:

The SI unit of current is ampere which measures the flow of electric charge across a surface at the rate of one coulomb per second.

5 0
3 years ago
An object with a mass of 0. 25 kg is undergoing simple harmonic motion at the end of a vertical spring with a spring constant, k
skelet666 [1.2K]

Answer:

1) The amplitude of the motion is approximately 0.274 meters.

2) The total energy of the object at any point of its motion is 16.892 joules.

Explanation:

1) An object under simple harmonic motion is conservative, since there is no dissipative forces acting during motion (i.e. friction, air viscosity). The amplitude of the motion can be found easily by Principle of Energy Conservation by the fact that maximum elastic potential energy (U_{e}), in joules, is equal to maximum translational kinetic energy (K), in joules:

U_{e} = K

\frac{1}{2}\cdot k \cdot A^{2} = \frac{1}{2}\cdot m \cdot v^{2} (1)

Where:

k - Spring constant, in newtons per meter.

A - Amplitude, in meters.

m - Object mass, in kilograms.

v - Speed of the object at equilibrium, in meters per second.

If we know that k = 450\,\frac{N}{m}, m = 0.25\,kg and v = 0.3\,\frac{m}{s}, then the amplitude of the motion is:

\frac{1}{2}\cdot k \cdot A^{2} = \frac{1}{2}\cdot m \cdot v^{2}

k\cdot A^{2} = m\cdot v^{2}

A = v\cdot \sqrt{\frac{m}{k} }

A = \left(0.3\,\frac{m}{s} \right)\cdot \sqrt{\frac{0.25\,kg}{0.3\,\frac{m}{s} } }

A \approx 0.274\,m

The amplitude of the motion is approximately 0.274 meters.

2) The total energy of the object (E), in joules, is found either by maximum elastic potential energy or by maximum translational kinetic energy, that is: (k = 450\,\frac{N}{m}, A \approx 0.274\,m)

E = U_{e}

E = \frac{1}{2}\cdot k\cdot A^{2}

E = \frac{1}{2}\cdot \left(450\,\frac{N}{m} \right) \cdot (0.274\,m)^{2}

E = 16.892\,J

The total energy of the object at any point of its motion is 16.892 joules.

7 0
3 years ago
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