Question

Using the diagram below, calculate the PE and KE of the ball at the top, middle, and bottom of a drop. SHOW YOUR WORK!!

Answer 1

Answer:

At the top

K.E = 0

P.E = 981 J

Mechanical energy is conserved

P.E is maximum

K.E = 0

At the middle

K.E = 981 J

P.E = 0

Mechanical energy is conserved

K.E is maximum

P.E = 0

At the bottom

K.E = 0

P.E = 981 J

Mechanical energy is conserved

K.E = 0

P.E is maximum

Explanation:

Given that

M= 5kg

H = 20 m

t = 7 s

According to conservation of energy,

At the top

K.E = 0

P.E = mgh

P.E = 5 × 9.81 × 20

P.E = 981 J

Mechanical energy is conserved

P.E is maximum

K.E = 0

At the middle

K.E = 981 J

P.E = 0

Mechanical energy is conserved

K.E is maximum

P.E = 0

At the bottom

K.E = 0

P.E = 981 J

Mechanical energy is conserved

K.E = 0

P.E is maximum

Given that

M= 5kg

H = 20 m

t = 7 s

At the top

K.E = 0

P.E = mgh

P.E = 5 × 9.81 × 20

P.E = 981 J

Mechanical energy is conserved

P.E is maximum

K.E = 0

At the middle

K.E = 981 J

P.E = 0

Mechanical energy is conserved

K.E is maximum

P.E = 0

At the bottom

K.E = 0

P.E = 981 J

Mechanical energy is conserved

K.E = 0

P.E is maximum

Explanation:

Given that

M= 5kg

H = 20 m

t = 7 s

At the top

K.E = 0

P.E = mgh

P.E = 5 × 9.81 × 20

P.E = 981 J

Mechanical energy is conserved

P.E is maximum

K.E = 0

At the middle

K.E = 981 J

P.E = 0

Mechanical energy is conserved

K.E is maximum

P.E = 0

At the bottom

K.E = 0

P.E = 981 J

Mechanical energy is conserved

K.E = 0

P.E is maximum