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3 years ago

Using the diagram below, calculate the PE and KE of the ball at the top, middle, and bottom of a drop. SHOW YOUR WORK!!

Physics

1 answer:

Orlov [11]3 years ago

5 0

Answer:

At the top

K.E = 0

P.E = 981 J

Mechanical energy is conserved

P.E is maximum

K.E = 0

At the middle

K.E = 981 J

P.E = 0

Mechanical energy is conserved

K.E is maximum

P.E = 0

At the bottom

K.E = 0

P.E = 981 J

Mechanical energy is conserved

K.E = 0

P.E is maximum

Explanation:

Given that

M= 5kg

H = 20 m

t = 7 s

According to conservation of energy,

At the top

K.E = 0

P.E = mgh

P.E = 5 × 9.81 × 20

P.E = 981 J

Mechanical energy is conserved

P.E is maximum

K.E = 0

At the middle

K.E = 981 J

P.E = 0

Mechanical energy is conserved

K.E is maximum

P.E = 0

At the bottom

K.E = 0

P.E = 981 J

Mechanical energy is conserved

K.E = 0

P.E is maximum

Given that

M= 5kg

H = 20 m

t = 7 s

At the top

K.E = 0

P.E = mgh

P.E = 5 × 9.81 × 20

P.E = 981 J

Mechanical energy is conserved

P.E is maximum

K.E = 0

At the middle

K.E = 981 J

P.E = 0

Mechanical energy is conserved

K.E is maximum

P.E = 0

At the bottom

K.E = 0

P.E = 981 J

Mechanical energy is conserved

K.E = 0

P.E is maximum

Explanation:

Given that

M= 5kg

H = 20 m

t = 7 s

At the top

K.E = 0

P.E = mgh

P.E = 5 × 9.81 × 20

P.E = 981 J

Mechanical energy is conserved

P.E is maximum

K.E = 0

At the middle

K.E = 981 J

P.E = 0

Mechanical energy is conserved

K.E is maximum

P.E = 0

At the bottom

K.E = 0

P.E = 981 J

Mechanical energy is conserved

K.E = 0

P.E is maximum

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Answer:

5365 N

Explanation:

v = Final velocity = 23 m/s

u = Initial velocity = -14 m/s (opposite direction)

m = Mass of ball = 145 g

t = Time taken = 1 ms

Impulse is given by

$J=m(v-u)$

Impulse is also given by

$J=Ft$

$Ft=m(v-u)\\\Rightarrow F=\dfrac{m(v-u)}{t}\\\Rightarrow F=\dfrac{0.145\times (23-(-14))}{1\times 10^{-3}}\\\Rightarrow F=5365\ N$

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Two identical resistors are connected first in series and second in parallel. The equivalent resistances of the two types of con

trasher [3.6K]

Answer:

$\frac{R_{s} }{R_{p} } =\frac{R_{1} }{R_{2} }+\frac{R_{2} }{R_{1} } +2$

Explanation:

We have series and parallel combination of two resisters $R_{1}$ and $R_{2}$ .

Series combination is

$R_{s}= R_{1}+R_{2}$ and Parallel is $R_{p} = (\frac{1}{R_{1}}+\frac{1}{R_{2}} )^-1$

Now dividing series equivalent resistance by parallel resistance gives us

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Indigenous people sometimes cooked in watertight baskets by placing enough hot rocks into the water to bring it to a boil. What

yaroslaw [1]

Answer:

The rock has a mass of 4.02 kg

Explanation:

Step 1: Data given

Mass of the rock = TO BE DETERMINED

Temperature of the rock = 500 °C

Mass of the water =4.24 kg

⇒ loses 0.044kg as vapor

Initial temperature of the water = 29°C

Final temperature = 100°C

Specific heat of rock = 0.20 kcal/kg °C

Specific heat of water = 1kcal/kg°C

Latent heat of vaporization = 539 kcal/kg

Step 2: formules

Qlost,rock + Qgained,water = 0

Qtotal,water = Qwater +Qvapor

Step 3: Calculate Qvapor

Qvapor = mass of vapor * Latent heat of vapor

Qvapor = 0.044kg * 539 kcal/kg = 23.716 kcal

Step 4: Calculate Qwater

Qwater = mass of water * specific heat * Δtemperature

Qwater = 4.196 kg * 1kcal/kg°C *( 100-29)

Qwater = 297.916 kcal

Step 5: Calculate Qwater,total

Qwater,total = Qwater + Qvapor

Qwater,total = 23.716 kcal + 297.916 = 321.632 kcal

Step 6: Calculate Qrock

Qrock = mass of rock * specific heat rock * Δtemperature

Qrock = mass of rock * 0.20 kcal/kg°C * (100-500)

Qrock = mass of rock * -80 kcal/kg

Step 7: Calculate mass of rock

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Qlost,rock = -Qgained,water

mass of rock * -80 kcal/kg = -321.632 kcal

mass of rock = 4.02 kg

The rock has a mass of 4.02 kg

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Harlamova29_29 [7]

Answer:

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This means that when a planet is further away from the Sun, it will move slower (because the line is longer, so it must move slower), while when the planet is closer to the Sun, it will move faster (because the line is shorter, so it must move faster).

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