Question

Solve the equation. \dfrac32 + b = \dfrac74 2 3 ​ +b= 4 7 ​ start fraction, 3, divided by, 2, end fraction, plus, b, equals, start fraction, 7, divided by, 4, end fraction b=b=b, equals

Answer 1

Answer:

1/4

Step-by-step explanation:

Answer 2

Given:

The equation is

$\dfrac{3}{2}+b=\dfrac{7}{4}$

To find:

The value of b.

Solution:

We have,

$\dfrac{3}{2}+b=\dfrac{7}{4}$

Subtracting both sides by $\dfrac{3}{2}$, we get

$b=\dfrac{7}{4}-\dfrac{3}{2}$

$b=\dfrac{7-2(3)}{4}$

$b=\dfrac{7-6}{4}$

$b=\dfrac{1}{4}$

Therefore, the value of b is $\dfrac{1}{4}$.