Answer:
Answer: 84 meters squared. (i.e. 84m^2).
Step-by-step explanation:
Area of the path = total area of path and plot - plot area only
First, let’s find the area of the plot:
20m x 20m = 400m^2
The path is 1m wide and runs all the way around, so, it describes an ‘outer square’ of 22m x 22m (2 x 1m larger because there are 1m of the path on each side).
The area of this ‘outer square’ is equivalent to the ‘total area of path and plot’
22m x 22m = 484m^2
So:
Area of the path = total area of path and plot - plot area only
= 484 - 400 = 84m^2
Answer:
I put it in the calc and it got
x=5i,−5i
Answer:
4x+5
Step-by-step explanation:
Answer:

Step-by-step explanation:
using the cosine ratio;

From the question, the side of the right angle triangle that is adjacent to the measured <a,(i.e BAC) is AC=24 and the hypotenuse is AB=25
This implies that,
