The radius of the circle tangent to sides AC and BC and to the circumcircle of triangle ABC.
r= 24.
<h3>What is the radius of the circle tangent to sides AC and BC and to the circumcircle of triangle ABC.?</h3>
Generally, the equation for side lengths AB is mathematically given as
Triangle ABC has side lengths
Where
- AB = 65,
- BC = 33,
- AC = 56.
Hence
r √ 2 · (89 √ 2/2 − r √ 2) = r(89 − 2r),
r = 89 − 65
r= 24.
In conclusion, The radius of the circle tangent to sides AC and BC and to the circumcircle of triangle ABC.
r= 24.
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Answer:
35.8 deg
Step-by-step explanation:
a/sin A = b/sin B
24/sin x = 39/sin 71.8
sin x = (24 * sin 71.8)/39
sin x = 0.584598
x = sin^-1 0.584598
x = 35.8 deg
Answer:
48in sq
Step-by-step explanation:
8*12/2=8*6=48
Answer:
160/147
Step-by-step explanation:
