Answer:
MRR = 1.984
Explanation:
Given that
Depth of cut ,d=0.105 in
Diameter D= 1 in
Speed V= 105 sfpm
feed f= 0.015 ipr
Now the metal removal rate given as
MRR= 12 f V d
d= depth of cut
V= Speed
f=Feed
MRR= Metal removal rate
By putting the values
MRR= 12 f V d
MRR = 12 x 0.015 x 105 x 0.105
MRR = 1.984
Therefore answer is -
1.944
Answer:
hello your question is incomplete attached below is the complete question and the detailed solution
Answer: A) 5.17 GHz
B) 1.01 GHz
Explanation:
Assuming the transistor is biased and considering the two conditions as given in A and B attached below is a detailed solution to the given problem
Answer:
C - airplane and grocery store
Explanation:
i hope this helps
Answer:
Other examples of reciprocating motion include piston pumps and compressors, roller pressure and tensioning systems, material testing devices, and insertion machines.
Explanation:
Answer:
head(faithful)
faithful_model<-lm(eruptions~waiting,data=faithful)
summary(faithful_model)
Explanation:
