Answer:
The viscosities of the oils are 0.967 Pa.s and 1.933 Pa.s
Explanation:
Assuming the two oils are Newtonian fluids.
From Newton's law of viscosity for Newtonian fluids, we know that the shear stress is proportional to the velocity gradient with the viscosity serving as the constant of proportionality.
τ = μ (∂v/∂y)
There are oils above and below the plate, so we can write this expression for the both cases.
τ₁ = μ₁ (∂v/∂y)
τ₂ = μ₂ (∂v/∂y)
dv = 0.3 m/s
dy = (0.06/2) = 0.03 m (the plate is centered in a gap of width 0.06 m)
τ₁ = μ₁ (0.3/0.03) = 10μ₁
τ₂ = μ₂ (0.3/0.03) = 10μ₂
But the shear stress on the plate is given as 29 N per square meter.
τ = 29 N/m²
But this stress is a sum of stress due to both shear stress above and below the plate
τ = τ₁ + τ₂ = 10μ₁ + 10μ₂ = 29
But it is also given that one viscosity is twice the other
μ₁ = 2μ₂
10μ₁ + 10μ₂ = 29
10(2μ₂) + 10μ₂ = 29
30μ₂ = 29
μ₂ = (29/30) = 0.967 Pa.s
μ₁ = 2μ₂ = 2 × 0.967 = 1.933 Pa.s
Hope this Helps!!!
Answer:
For Figure Below, if the elevation of the benchmark A is 25.00 m above MSL:
1. Using the Rise and Fall Method, find the reduced level for all points. (Construct the Table)
2. Using HPC Method, find the reduced level for all points. ( Construct the Table).
3. Show all required Arithmetic checks for your work. For Item 1 and 2.
4. What is the difference in height between points H and D?
5. What is the gradient of the line connecting A and J, knowing that horizontal distance = 200
m.
Answer:
an importer
Explanation:
Jason's petrochems depends on imported intermediates for its production/processing. From the question, the firm imports chemical intermediates, processes them in its laboratories before selling them. It also uses the intermediates to produce various fertilizers and solvents. Essentially its feed stocks ( inputs) are wholly imported from different countries. Hence the firm is an import dependent petrochemical complex.
Depends on your defense and probably
