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Helga [31]
3 years ago
9

Which best explains Susan B Anthony purpose in her speech “Women’s rights to the suffrage”

Engineering
2 answers:
Furkat [3]3 years ago
6 0

Answer:

She wrote and delivered a speech in 1873, which came to be known as the “Women's Rights to the Suffrage” speech. In her address, she lets the audience know of her “crime” of voting. She reminds the listener that the Constitution of the United States says “we the people” and does not exclude women as people

Arte-miy333 [17]3 years ago
3 0

Answer:

D. To show why she was justified in voting.

Explanation:

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Close to 16 billion pounds of ethylene glycol (EG) were produced in 2013. It previously ranked as the twenty-sixth most produced
bekas [8.4K]

Answer:

a) 0.684

b) 0.90

Explanation:

Catalyst

EO + W → EG

<u>a) calculate the conversion exiting the first reactor </u>

CAo = 16.1 / 2   mol/dm^3

Given that there are two stream one  contains 16.1 mol/dm^3 while the other contains   0.9 wt% catalyst

Vo = 7.24 dm^3/s

Vm = 800 gal = 3028 dm^3

hence Im = Vin/ Vo = (3028 dm^3) / (7.24dm^3/s) = 418.232 secs = 6.97 mins

next determine the value of conversion exiting the reactor ( Xai ) using the relation below

KIm = \frac{Xai}{1-Xai}  ------ ( 1 )

make Xai subject of the relation

Xai = KIm / 1 + KIm  ---  ( 2 )

<em>where : K = 0.311 ,  Im = 6.97   ( input values into equation 2 )</em>

Xai = 0.684

<u>B) calculate the conversion exiting the second reactor</u>

CA1 = CA0 ( 1 - Xai )

therefore CA1 = 2.5438 mol/dm^3

Vo = 7.24 dm^3/s

To determine the value of the conversion exiting the second reactor  ( Xa2 ) we will use the relation below

XA2 = ( Xai + Im K ) / ( Im K + 1 ) ----- ( 3 )

<em> where : Xai = 0.684 , Im = 6.97,  and K = 0.311  ( input values into equation 3 )</em>

XA2 = 0.90

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4 0
3 years ago
A heat engine is coupled with a dynamometer. The length of the load arm is 900 mm. The spring balance reading is 16. Applied wei
miss Akunina [59]

Answer:

P = 80.922 KW

Explanation:

Given data;

Length of load arm is 900 mm = 0.9 m

Spring balanced  read 16 N

Applied weight is 500 N

Rotational speed is 1774 rpm

we know that power is given as

P = T\times \omega

T Torque = (w -s) L = (500 - 16)0.9 = 435.6 Nm

\omega angular speed =\frac{2 \pi N}{60}

Therefore Power is

P =\frac{435.6 \time 2 \pi \times 1774}{60} = 80922.65  watt

P = 80.922 KW

4 0
3 years ago
Por favor. alguien me comunique con fatimalisethmateual
lions [1.4K]
Wait why do you want me to
7 0
3 years ago
Harmonic excitation of motion is represent as
Gennadij [26K]

Harmonic excitation refers to a sinusoidal external force of a certain frequency applied to a system. ... Resonance occurs when the external excitation has the same frequency as the natural frequency of the system. It leads to large displacements and can cause a system to exceed its elastic range and fail structurally.

6 0
3 years ago
) An ammonia nitrogen analysis performed on a wastewater sample yielded 30 mg/L as nitrogen. If the pH of the sample was 8.5, de
Delicious77 [7]

Answer:

NH_4^+ = 2.5 mg/lt

Explanation:

Given data:

Ammonia Nitrogen 30 mg/L

pH = 8.5

-log[H +] = 8.5

[H +] = 10^{-8.5}

NH_4 ^{+} ⇄ H^{+} + NH_3

Rate constant is given as

K_a = \frac{[H^{+}] [NH_3]}{NH_4^{+}} ...........1

K_a = 5.6 \times 10^{-10}

Total ammonia as NItrogen is given as 30 mg/l

\%NH_4^{+} = \frac{ [NH_4] \times 100}{[NH_4^{+}] + [NH_3]}

                    = \frac{100}{\frac{NH_4^+}{NH_4^+} +\frac{NH_3^+}{NH_4^+}}

                    = \frac{100}{1+ \frac{NH_3^+}{NH_4^+}} .....2

from equation 1 we have

\frac{NH_3^+}{NH_4^+} =\frac{K_a}{[H^+]} = \frac{5.6\times 10^{-10}}{10^{8.5}}

plug this value in equation 2 we get

\%NH_4^{+} = 84.96 \%

Total ammonia as N = 30 mg/lt

NH_4^+ = \frac{84.96}{100} \times 30 = 25.5 mg/lt

7 0
3 years ago
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