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stich3 [128]
4 years ago
12

In a quadrilateral ABCD, AB || DC and AD || BC. Find the perimeter of triangle COD if the diagonals of the quadrilateral interse

ct each other at point O and AC = 20in, BD = 20in, AB = 13in.

Mathematics
1 answer:
aalyn [17]4 years ago
4 0
Draw a diagram as shown below.

The diagonals are equal in length. Because AB || DC and AD || BC, the quadrilateral is a square.

Because the diagonals bisect each other at O, therefore
DO = BO = 10.
Likewise,
AO = CO = 10

Because AB = 13, therefore DC = 13.
The perimeter of ΔCOD is CO + CD + DO = 10 + 13 + 10 = 33 in

Answer: 33 in

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Step-by-step explanation:

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<span>thus arranging from greatest to least:6km, 60m, 600 cm or 6000mm</span>

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I need help I can’t figure it out
dusya [7]

Answer:

\large\boxed{\dfrac{41p}{70q^4(r-9)^2}}

Step-by-step explanation:

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7 0
3 years ago
When solving negative one over five -1/5 (x − 25) = 7, what is the correct sequence of operations
aleksandr82 [10.1K]

The solution would be like this for this specific problem:

 

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\left( { - 5} \right)&#10;\cdot \left( { - \frac{1}{5}} \right) = 1

 

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Answer:

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Step-by-step explanation:

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