In a quadrilateral ABCD, AB || DC and AD || BC. Find the perimeter of triangle COD if the diagonals of the quadrilateral interse
ct each other at point O and AC = 20in, BD = 20in, AB = 13in.
1 answer:
Draw a diagram as shown below.
The diagonals are equal in length. Because AB || DC and AD || BC, the quadrilateral is a square.
Because the diagonals bisect each other at O, therefore
DO = BO = 10.
Likewise,
AO = CO = 10
Because AB = 13, therefore DC = 13.
The perimeter of ΔCOD is CO + CD + DO = 10 + 13 + 10 = 33 in
Answer: 33 in
The diagonals are equal in length. Because AB || DC and AD || BC, the quadrilateral is a square.
Because the diagonals bisect each other at O, therefore
DO = BO = 10.
Likewise,
AO = CO = 10
Because AB = 13, therefore DC = 13.
The perimeter of ΔCOD is CO + CD + DO = 10 + 13 + 10 = 33 in
Answer: 33 in
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Answer:
3. 3 : 5; 3: 5
Step-by-step explanation:
First, let's find the leght of the sides of each octagon.
The area of an octagon is defined by
Replacing the area
Therefore, the side of the first octagon is 1.6 inches long.
Its perimeter is:
Therefore, the side of the second octagon is 3.8 inches long.
Its perimeter is .
Now, let's divide to find each ratio:
(the ratio between sides).
(the ratio between perimeters).
Therefore, the closest ratio is 3. 3 : 5; 3: 5