Answer:
option D
Explanation:
given,
length of the pipe, L = 0.96 m
Speed of sound,v = 345 m/s
Resonating frequency when both the end is open
n is the Harmonic number
2nd overtone = 3rd harmonic
so, here n = 3
now,
f = 540 Hz
The common resonant frequency of the string and the pipe is closest to 540 Hz.
the correct answer is option D
With the information given, one can presume that:
Work = F • d (so W = 875,000 J)
The equation for power is:
P = W/t (so P = 19444.4 Watts)
1 Watt = 1000 Kilowatts
So the answer would be 19,444,444 kW
<span>C. surface tension of the water.</span>
The correct option is (A) 2.5 m/s
Explanation:
Since,
v = fλ ---- (1)
where v = speed of the wave
f = frequency of the wave = 5 Hz
λ = wavelength of the wave = 0.5
Plug in the value in (1):
(1) => v = 5 * 0.5
v = 2.5 m/s