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3 years ago

11

The amount of usable energy from anaerobic respiration is less than the amount of useable energy from aerobic respiration becaus

e
A. aerobic respiration produces products that are not completely broken down
B. the waste products of anaerobic respiration contain a lot of unprocessed energy C. the waste products of anaerobic respiration contains no more useable energy D.aerobic respiration is not as efficient

2 answers:

djyliett [7]3 years ago

6 0

B. The waste products of anaerobic respiration contain a lot of unprocessed energy ^-^

Ann [662]3 years ago

5 0

B. The waste products of anaerobic respiration contain a lot of unprocessed energy.

Hope this helps!

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Vascular plants can be divided into three categories. These categories are

Evgesh-ka [11]

I believe the answer here is <span>C).seedless, seed (nonflowering), and seed (flowering).</span><span>
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6 0

3 years ago

When you push a child on a swing, your action is most effective when your pushes are timed to coincide with the natural frequenc

OleMash [197]

Answer:

$T = 4.48 s$

we can see that this time period is independent of the mass of the child so answer would be same if the child mass is different

Explanation:

Natural frequency of a simple pendulum of L length is given as

$f = \frac{1}{2\pi}\sqrt{\frac{g}{L}}$

so the time period of the oscillation is given as

$T = 2\pi \sqrt{\frac{L}{g}}$

so we will have

$L = 5 m$

$T = 2\pi\sqrt{\frac{5}{9.81}}$

$T = 4.48 s$

also from above formula we can see that this time period is independent of the mass of the child so answer would be same if the child mass is different

3 0

3 years ago

Is NaCH an element? Why or why not?

amm1812

<span>NaCH is not an element, it is a compound. An element can be found and identified on the periodic table to elements. A compound is a combination of two of more elements. NaCH is composed of three elements: Na (sodium), C (carbon) and H (hydrogen), making it a compound.</span>

3 0

3 years ago

A solenoid 91.0 cm long has a radius of 1.50 cm and a winding of 1300 turns; it carries a current of 3.60 A. Calculate the magni

irinina [24]

The magnitude of the magnetic field inside the solenoid is $6.46 \times 10^{-3} \ T$ .

The given parameters;

<em>length of the solenoid, L = 91 cm = 0.91 m</em>
<em>radius of the solenoid, r = 1.5 cm = 0.015 m</em>
<em>number of turns of the solenoid, N = 1300 </em>
<em>current in the solenoid, I = 3.6 A</em>

The magnitude of the magnetic field inside the solenoid is calculated as;

$B = \mu_0 nI\\\\B = \mu_o(\frac{ N}{L} )I\\\\$

where;

$\mu_o$ is the permeability of frees space = 4π x 10⁻⁷ T.m/A

$B = (4\pi \times 10^{-7}) \times (\frac{1300}{0.91} ) \times 3.6\\\\B = 6.46 \times 10^{-3} \ T$

Thus, the magnitude of the magnetic field inside the solenoid is $6.46 \times 10^{-3} \ T$ .

Learn more here:brainly.com/question/17137684

7 0

2 years ago

Given one mole of diamond vs one mole of graphite,

grandymaker [24]

Answer:

The pressure is $P= - 6.39*10^8Pa$

The temperature is $T =1218.63 K$

Explanation:

Generally Gibbs free energy is mathematically represented as

$G = E + PV -TS$

Where E is the enthalpy

PV is the pressure volume energy (i.e PV energy)

S is the entropy

T is the temperature

For stability to occur the Gibbs free energy must be equal to zero

Considering Diamond

So at temperature of T = 300 K

$E + PV - TS = 0$

making P the subject

$P = \frac{TS-E}{V}$

Now substituting 300 K for T , 2900 J for E ,

$3.42cm^3 = \frac{3.42}{1*10^6} = 3.42*10^{-6}m^3$ for V and $2.38 J/K$ for S

$P = \frac{(300 * 2.38)- 2900}{3.42*10^{-6}}$

$P= - 6.39*10^8Pa$

The negative sign signifies the direction of the pressure

Given that $P = 1*0^5Pa$

making T the subject

$T = \frac{PV+E}{S}$

Substituting into the equation

$T = \frac{1*10^5 * 3.42 *10^{-6}+2900}{2.38}$

$T =1218.63 K$

7 0

3 years ago

Read 2 more answers