Answer:
0.833 N
Explanation:
Formula for Kinetic Energy
Formula for Potential Energy
First we need to find the vertical distance between the maximum-angle position and the pendulum lowest point:
Using the swinging point as the reference, the vertical distance from the maximum-angle (34 degree) position to the swinging point is:
At the lowest position, pendulum is at string length to the swinging point, which is 1.2 m. Therefore, the vertical distance between the maximum-angle position and the pendulum lowest point would be
y = 1.2 - 1 = 0.2 m.
As the pendulum is traveling from the maximum-angle position to the lowest point position, its potential energy would be converted to the kinetic energy.
By law of energy conservation:
Substitute and y = 0.2 m:
At lowest point, pendulum would generate centripetal tension force on the string:
We can substitute mass m = 0.25, rotation radius L = 1.2 m and v = 2 m/s:
Answer: Northwest.
Explanation:
After the collision the second object which was at rest would change its direction and move towards the Northwest. The object in motion was coming from the east and traveling towards the west, where it deflects against a stationery object which changes its direction to southeast. And the object which was at rest moves toward the northwest.
Answer:
Measurement is the act or the process of finding the size, quantity or degree of something.
Explanation:
We can measure the length, weight, and capacity (volume) of any given object.
Answer:
2.4564 m/s
Explanation:
Number of waves in 1 second
This is the frequency 0.267 Hz
The distance mentioned in the question is the
= Wavelength = 9.2 m
The speed of wave is
The speed of the wave is 2.4564 m/s
The amount of work that has been done on the projectile by air friction is 7,569.2 J.
<h3>
Work done by air friction on the projectile</h3>
The work done by air friction on the projectile is calculated as follows;
W = ΔK.E
W = ¹/₂mvf² - ¹/₂mv₀²
where;
- vf is the final velocity = 85 m/s
- v₀ is the initial vertical velocity = 100 x sin(20) = 34.2 m/s
W = ¹/₂m(vf² - v₀²)
W = ¹/₂ x 2.5 (85² - 34.2²)
W = 7,569.2 J
Thus, the amount of work that has been done on the projectile by air friction is 7,569.2 J.
Learn more about work done here: brainly.com/question/8119756
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