A car starts with an initial speed of 12 m/s and accelerates at 3 m/s/s for 5 seconds

Assume a beam with stirrups inclined at 60o angle with respect to the longitudinal steel resisting cracks developing at 45o angl

arlik [135]

Answer:

Shear resistance of a inclined stirrup is given by

Vᵇ = Asb(0.95*Fy)(cos α - sin α*cotβ) ((d-d')/sᵇ)

Explanation:

The shear resistance is checked in accordance with BS8110: Part 1, section 3.5.5. Shear resistance of a inclined stirrup is given by

Vᵇ = Asb(0.95*Fy)(cos α - sin α*cotβ) ((d-d')/sᵇ)

where,

Vᵇ=design shear resistance of inclined bars

Asb=cros-sectional area of the inclined bars

Fy=characteristics strength of the stirrups

α=angle between the inclined bars and the axis of the beam

β=angle between the compression strut of inclined bars and the axis of the beam

sᵇ=spacing of the inclined bars

d= effective depth and d'=effective depth minus cover to reinforcement

The shear stress is given by

v=V/bd

where V is the shear force due to ultimate loads. If v is shear stress

5 0

3 years ago

FIGURE 4.1 shows a rectangular wire loop 0.3 m x 0.2 m moving horizontally to the right at 12 ms -1 in a uniform magnetic field

timama [110]

<h3>Given :- </h3>

Length of the rectangular wire, L=0.3 m
Width of the rectangular wire, b=0.2m
Magnetic field strength, B=0.8 T
Velocity of the loop, v =12 m/s
Induced Current, I = 3 A

$\underline{\underline{\large\bf{Solution:-}}}\\$

(I) Emf developed,E in the loop is given as:

$\begin{gathered}\\\implies\quad \sf E = BLv \\\end{gathered}$

$\begin{gathered}\\\implies\quad \sf E = 0.8 \times 0.3 \times 12 \\\end{gathered}$

$\begin{gathered}\\\implies\quad \sf E = 2.88 V \\\end{gathered}$

$\longrightarrow$ I = E/R

$\quad$ R = E/I

where

R = resistance
E = Induced EMF
I = Current

$\begin{gathered}\\\implies\quad \sf R = \frac{2.88}{3} \\\end{gathered}$

$\begin{gathered}\\\implies\quad \boxed{\sf{ R = 0.96 \;ohm}}\\\end{gathered}$

(ii) The direction of current induced is from P to Q which is given by B × V vector . It may also be explained by Lenz law. Since magnetic field is from S to N . The fingers of the right hand are placed around the wire so that the curling of fingers will show the direction of the magnetic field produced by the wire then the thumb points in the direction of current flow which is from P to Q.

3 0

2 years ago

The constant forces F1 = 8 + 29 + 32 N and F2 = 48 - 59 - 22 N act together on a particle during a displacement from the point A

marshall27 [118]

Answer:

-600 J

Explanation:

F₁ = 8i +29 j + 32k

F₂ = 48 i - 59 j - 22 k

F = F₁ +F₂ = 8i +29 j + 32k +48 i - 59 j - 22 k

F = 56i - 30 j + 10 k

displacement d = ( 0 - 20 )i + ( 0 - 15 )j + ( 7 -0) k

d = - 20 i - 15 j + 7 k

Work Done = F dot product d

F . d = - 56 x 20 - 30 x - 15 + 10 x 7

= - 1120 +450 + 70

= -600 J

5 0

3 years ago

What can destroy stuff yet does not have any mass

Artist 52 [7]

If energy could be created or destroyed, all of our ideas of how the world works ... Historically, of course not all the forms of energy were known to begin with. ... too messy or complicated to make sense, we would have had to give up the law. ... can be converted into rest mass and back again (particle physicists do this every )

3 0

3 years ago

How is Newton’s first law demonstrated by your zip line

Nikitich [7]

Newton's First Law: An object in motion stays in motion, an object at rest stays at rest unless an unbalanced force acts upon it. For example, when zipping down the zip line you will stay in motion unless an outside force interferes. ... The more mass the more force needed.

4 0

3 years ago