I'm pretty sure the expression would be (if students = s) S - (0.3S + 40)
1/4 x 4/7
do the top numbers first. 1 x 4 is 4do bottom numbers next 4 x 7 is 28
that leaves you with 4/28. But you have to reduce.
4/28 = 2/14 = 1/7 (notice I just cut both the top and bottom numbers in half each time I reduced until I couldn't reduce any more).
So, final answer is 1/7
Answer:
- Q1. No solution
- Q2. (5, 6)
- Q3. Infinitely many solutions
- Q4. No solution
- Q5. (2, 3)
Step-by-step explanation:
Q1.
- y = -1/3x - 1
- x + 3y = -12
<u>Solution</u>
- x + 3(-1/3x - 1) = -12
- x - x - 3 = -12
- -3 = -12
No solution
Q2
<u>Solution</u>
(5, 6)
Q3
<u>Solution</u>
- 6x + 2(-3x + 3) = 6
- 6x - 6x + 6 = 6
- 6 = 6
Infinitely many solutions
Q4
- - 5x + y = 1
- - 10x + 2y = -2 ⇒ -5x + y = -1
<u>Solution</u>
No solution
Q5
<u>Solution</u>
- 1/2x + 2 = x + 1
- 1/2x = 1
- x = 2
- y = 3
(2, 3)
Answer:
the answer is A. 2370 sq. in
Step-by-step explanation:
area of the triangles first
A = 1/2 ad
a = (45 in) (20 in)
a = 1/2 (900 sq in)
a = 450 sq in
***remember to multiply 450 * 2 because you have 2 triangles***
Total area of both triangles is 900 sq. in.
Find the area of the 3 rectangles A = LW
1st rectangle and 2nd rectangle
a = cb
a = (30 in) (14 in)
a = 420 sq in. (make sure you add this again in the Total Surface area)
3rd rectangle
a = ab
a = (45 in) (14 in)
a = 630 sq. in
Total Surface area = 2 (1/2 ad) + 2(cb) + (ab)
= 2 (450 sq. in) + 2 (420 sq. in) + 630 sq. in
= 900 sq. in + 840 sq. in + 630 sq. in
= 2370 sq. in
You cannot combine any the terms because x and y are two different variables. that is the most simplified you can get.
