All categories

2 years ago

I Don't know how to do this, please help me!! :( number 19

Mathematics

2 answers:

notka56 [123]2 years ago

7 0

All angles of a triangles equal to 180, 180 degrees minus 28 and 103= the missing angle, 49!

Vikentia [17]2 years ago

6 0

Answer:

Step-by-step explanation:

#19. m∠JML = 126°

#20. $P_{JKLM}$ = 50 units

You might be interested in

The quantity, Q, of a drug in the blood stream begins with 250 mg and decays to one-fifth its value over every 90 minute period.

Mazyrski [523]

Answer:

$a=250 \, mg\\\\b=5\\\\T= 90'$

Step-by-step explanation:

We have that $Q(t) = a\cdot b^{-\frac{t}{T}} \\$

Where t is the time (in minutes) and for the sake of dimensional consistency, let's assume that T is also in minutes, b is an adimensional number, and a is in mg. So we will have Q in mg as a consequence.

We now want to find out what values these constants might take. Let's see what happens when $t=0$ , that is, just as we start. At that point, we have that the amount of drug in the bloodstream must be equal to 250mg, thus:

$Q(0)= a\cdot b ^{-\frac{0}{T} }=250\,mg\\Q(0)= a=250\,mg$

We have found the constant $a$ ! It is the initial amount of drug! we have made use of the fact that any number raised to the 0th power is equal to one.

Now, we know that every 90 minutes, the amount of drug decreases to one fifth of its former value. How do we put this in mathematical form? Like so:

$Q(t+90')=Q(t)/5$

That is, 90 minutes after time t the amount of drug will be one fifth of the amount of drug at time t. Let's expand the last equation:

$Q(t+90')=Q(t)/5\\\\a\cdot b^{-\frac{t+90'}{T} }=a\cdot b^{-\frac{t}{T} }/5\\\\ b^{-\frac{t+90'}{T} }=b^{-\frac{t}{T} }/5\\\\b^{-\frac{t}{T} }b^{-\frac{90'}{T} }=b^{-\frac{t}{T} }/5\\\\b^{-\frac{90'}{T} }=\frac{1}{5}$

Now the last expression isn't enough to determine both T and b, but that also means that we have some freedom in how we choose them. What seems most simple is to pick $T=90'$ and thus we will get:

$b^{-1 }=\frac{1}{5}\\\\\frac{1}{b}= \frac{1}{5}\\\\b=5$

And that is our final result.

3 0

2 years ago

bobby pays a $25 membership free to join YMCA gym. This gym allows members to attend any exercise class for only $4. The linear

blagie [28]

Answer:

Step-by-step explanation:

T = 4c + 25....where c = # of classes and T = total cost

2 classes...so sub in 2 for c and solve for T

T = 4(2) + 25

T = 8 + 25

T = 33 <==== with 2 classes ,its $ 33

4 classes....so sub in 4 for c and solve for T

T = 4(4) + 25

T = 16 + 25

T = 41 <==== with 4 classes, its $ 41

8 classes....sub in 8 for c

T = 4(8) + 25

T = 32 + 25

T = $ 57 <==== with 8 classes, its $ 57

10 classes...sub in 10 for c

T = 4(10) + 25

T = 40 + 25

T = 65 <===== with 10 classes, its $ 65

7 0

2 years ago

I NEED HELP ASAP PLEASEE THANK YOUUU

Viefleur [7K]

Answer:

Step-by-step explanation:

4 0

1 year ago

Read 2 more answers

In the xy-plane above, o is the center of the circle, and the measure of

Marina86 [1]

N the xy-plane above, O is the center of the cirlce. In the xy-plane above, O is the center of the cirlce, and the measure of angle AOB is pie/a radians

7 0

2 years ago

A function has x-intercept 3 and y-intercept 2. Which of the functions below could be this function?

Sergeeva-Olga [200]

we are given

x-intercept is 3

so,

a=3

y-intercept is 2

b=2

now, we can intercept formula of line

$\frac{x}{a} +\frac{y}{b}=1$