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nasty-shy [4]
3 years ago
13

How many moles are equal to 12.65 grams of Al2(SO4)3?

Chemistry
1 answer:
____ [38]3 years ago
5 0

Answer:

0.03697 mol Al₂(SO₄)₃

General Formulas and Concepts:

<u>Chemistry - Atomic Structure</u>

  • Reading a Periodic Table
  • Using Dimensional Analysis

Explanation:

<u>Step 1: Define</u>

12.65 g Al₂(SO₄)₃

<u>Step 2: Identify Conversions</u>

Molar Mass of Al - 26.98 g/mol

Molar Mass of S - 32.07 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of Al₂(SO₄)₃ - 2(26.98) + 3(32.07) + 12(16.00) = 342.17 g/mol

<u>Step 3: Convert</u>

<u />12.65 \ g \ Al_2(SO_4)_3(\frac{1 \ mol \ Al_2(SO_4)_3}{342.17 \ g \ Al_2(SO_4)_3} ) = 0.03697 mol Al₂(SO₄)₃

<u>Step 4: Check</u>

<em>We are given 4 sig figs. Follow sig fig rules and round.</em>

We already have 4 sig figs in the final answer, so no need to round.

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