The complete ionic equation is used to describe the chemical reaction while also clearly indicating which of the reactants and/or products exist primarily as ions in aqueous solution. To write the complete ionic equation: Start with a balanced molecular equation.
If it has 2 or more non-metals as well as a metal
Answer:
Explanation:
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As you move across a row from left to right in the periodic table, atomic numbers of elements increase. So the answer is letter b. increase.
Answer: -
24.24 mL
Explanation: -
Mass of CaCO₃ = 1.212 g
Molar mass of CaCO₃ = 40 x 1 +12 x 1 + 16 x 3 = 100 g / mol
Number of moles of CaCO₃ = ![\frac{1.212 g}{100 g/ mol}](https://tex.z-dn.net/?f=%20%5Cfrac%7B1.212%20g%7D%7B100%20g%2F%20mol%7D%20%20)
= 0.01212 mol
The balanced chemical equation for the reaction that occurs when CaCO₃ is added to HCl is
CaCO₃ + 2HCl --> CaCl₂ + H₂O + CO₂
From the equation we see
1 mol of CaCO₃ reacts with 2 mol of HCl
0.01212 mol of CaCO₃ react with ![\frac{2 mol HCl x 0.01212 mol CaCO₃}{1 mol CaCO₃}](https://tex.z-dn.net/?f=%20%5Cfrac%7B2%20mol%20HCl%20x%200.01212%20mol%20CaCO%E2%82%83%7D%7B1%20mol%20CaCO%E2%82%83%7D%20%20)
= 0.02424 mol of HCl
Strength of HCl = 1 M
Volume of HCl required = Number of moles of HCl / strength of HCl
= 0.02424 mol / 1 M
= 0.02424 L
= 0.02424 x 1000 mL
= 24.24 mL