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shtirl [24]
3 years ago
8

An equation for the line that passes through the points (6, -6) and (-4, 6) .

Mathematics
1 answer:
vivado [14]3 years ago
8 0

Answer:

y = -6/5x + 6/5

Step-by-step explanation:

equation formula is y = mx + b

m = slope

slope = change in y / change in x = (6 - -6) / (-4 - 6) = 12/-10 = -6/5

So m = -6/5

Now to find b, substitute one of the coordinates. Let's use (6, -6)

y = -6/5x + b

-6 = -6/5(6) + b

-6 = -36/5 + b

6/5 = b

So equation is y = -6/5x + 6/5

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erma4kov [3.2K]

25:1 is the answer.

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3 years ago
A store sells both cold and hot beverages. Cold beverages, c, cost $1.50, while hot beverages, h, cost $2.00. On Saturday, drink
ra1l [238]

Answer:

The number of hot beverages sold were 45 and the number of cold beverages sold were 180.

Step-by-step explanation:

Let the number of cold  beverages sold be c

And the number of hot beverages sold be h

According to the question:

c=4\times h...

$ 1.5\times c + 2\times h = Sale of any day

Part1:

For Saturday.

The sale is of $360

then

$ 1.5 \times c + $ 2 \times h =$ 360

Part 2:

Following the method of substitution.

And plugging the values of c=4\times h...in equation where the sales of Saturday is given.

1.5\times c + 2\times h =360

1.5\times 4\times h + 2 \times h =360

6\times h + 2\times h= 360

8\times h=360

Dividing both sides with 8.

h=\frac{360}{8}

h=45

Inserting h=45 in c=4 \times h...

we have c=4\times 45 = 180

So the number of hot beverages sold were 45 and the number of cold beverages sold were 180.

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Find x, when p(x) = -1,
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Answer:

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Step-by-step explanation:

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Suppose that a fast food restaurant decides to survey its customers to gauge interest in a breakfast menu. After surveying multi
Harlamova29_29 [7]

Answer:

ME= \frac{Width}{2}=\frac{0.078}{2}=0.039

\hat p =0.688+0.039=0.727

\hat p =0.766-0.039=0.727

Step-by-step explanation:

Assuming that the confidence interval is (0.688; 0.766)

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The population proportion have the following distribution  

p \sim N(p,\sqrt{\frac{p(1-p)}{n}})  

The confidence interval would be given by this formula  

\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}  

For the 95% confidence interval the value of \alpha=1-0.95=0.05 and \alpha/2=0.025, with that value we can find the quantile required for the interval in the normal standard distribution.  

z_{\alpha/2}=1.96  

Use the confidence interval to find the point estimate and margin of error for the proportion

The margin of error is given by :

Me=z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}

And for our case we can find the width of the confidence interval like this:

Width =0.766-0.688=0.078

And the estimation for the margin of error would be given by:

ME= \frac{Width}{2}=\frac{0.078}{2}=0.039

Now we can find th point of estimate adding the margin of error to the lower limit of the interval or subtracting the margin of error to the upper limit, like this:

\hat p =0.688+0.039=0.727

\hat p =0.766-0.039=0.727

4 0
3 years ago
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