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Sophie [7]
3 years ago
14

Please help if you are an expert or ace or whatever in math I need answers to these questions please!

Mathematics
1 answer:
DiKsa [7]3 years ago
5 0
6t=273.3
t=273/6
t=$45.5


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Find the coefficient for 3f+5
Papessa [141]

Answer:

3f5 Changes made to your input should not affect the solution:

(1): "f5"   was replaced by   "f^5". final result

3f5

Step-by-step explanation:

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. In which of the problems below would applying the multiplicative inverse be the best first step in determining a solution to t
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Answer:

B

Step-by-step explanation:

In The rest of the problems, you add or subtract first.

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2.- Supóngase que los diámetros de los tornillos fabricados por una compañía están distribuidos normalmente con una media de 0.2
Sergio [31]

Answer:

7.30167%

Step-by-step explanation:

Usando la fórmula de puntuación z

z = (x-μ) / σ, donde x es la puntuación bruta, μ es la media de la población y σ es la desviación estándar de la población

Para x <0.20 pulgadas

z = 0.20 - 0.25 / 0.02

z = -2.5

Valor de probabilidad de Z-Table:

P (x <0.20) = 0.0062097

Para x> 0.28 pulgadas

z = 0.28 - 0.20 / 0.02

z = 1.5

Valor de probabilidad de Z-Table:

P (x <0.28) = 0.93319

P (x> 0.28) = 1 - P (x <0.28) = 0.066807

La probabilidad de que se produzcan tornillos defectuosos cuando el tornillo se considera defectuoso si su diámetro es inferior a 0.20 pulgadas o superior a 0.28 pulgadas es

P (x <0.20) + P (x> 0.28)

= 0.0062097 + 0.066807

= 0.0730167

Conversión a porcentaje

= 0.0730167 × 100

= 7.30167%

El porcentaje de tornillos defectuosos producidos es

7.30167%

3 0
3 years ago
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