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3 years ago

How many grams of calcium phosphate can be produced when 89.3 grams of calcium chloride reacts with excess sodium phosphate?

1 answer:

5 0

Balanced chemical equation is
3CaCl2 +2Na3PO4-->6NaCl +Ca3(PO4)2
moles of CaCl2 =89.3g/[ (35.5x2) +40]=0.805moles
from the equation above the ratio of CaCl2 to Ca3(PO4)2 is 3:1 therefore the moles of Ca3(PO4)2 is 0.809/3=0.268moles
mass is therefore 0.268 x310.18(R.F.M of Ca3(PO4)2 ) =83.23grams

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(4) Calculate the % of a compound that can be removed from liquid phase 1 by using ONE to FOUR extractions with a liquid phase 2

maksim [4K]

Answer:

One extraction: 50%

Two extractions: 75%

Three extractions: 87.5%

Four extractions: 93.75%

Explanation:

The following equation relates the fraction q of the compound left in volume V₁ of phase 1 that is extracted n times with volume V₂.

qⁿ = (V₁/(V₁ + KV₂))ⁿ

We also know that V₂ = 1/2(V₁) and K = 2, so these expressions can be substituted into the above equation:

qⁿ = (V₁/(V₁ + 2(1/2V₁))ⁿ = (V₁/(V₁ + V₁))ⁿ = (V₁/(2V₁))ⁿ = (1/2)ⁿ

When n = 1, q = 1/2, so the fraction removed from phase 1 is also 1/2, or 50%.

When n = 2, q = (1/2)² = 1/4, so the fraction removed from phase 1 is (1 - 1/4) = 3/4 or 75%.

When n = 3, q = (1/2)³ = 1/8, so the fraction removed from phase 1 is (1 - 1/8) = 7/8 or 87.5%.

When n = 4, q = (1/2)⁴ = 1/16, so the fraction removed from phase 1 is (1 - 1/16) = 15/16 or 93.75%.

5 0

3 years ago

Which particles that make up an atom are involved in nuclear reactions?

Bezzdna [24]

Answer:

protons and neutrons- second choice

6 0

3 years ago

Please Help Meeee.<br> Best answer will get brainliest.

fiasKO [112]

Answer:Yes I am very good at acid

Explanation:

7 0

3 years ago

Read 2 more answers

Part A

inysia [295]

Pressure of the gas inside the container is 662.59 torr.

<h3>What is ideal gas law?</h3>

The ideal gas law (PV = nRT) connects the macroscopic characteristics of ideal gases. An ideal gas is one in which the particles are both non-repellent and non-attractive to one another (have no volume).

The general law of ideal gas can be applied here: PV is equal to nRT, where P is the gas pressure in atm.

V is the number of moles of the gas in a mole, and n is the volume of the gas in L. R is the universal gas constant. T is the temperature(Kelvin) of the gas.

If P and T are different values and n and V are constants, then

(P₁T₂) = (P₂T₁).

P₁ = 735 torr, T₁ = 29°C + 273 = 302 K,

P₂ = ??? torr, T₂ = 62°C + 273 = 335 K.

∴ P₂ = (P₁T₂)/(P₁) = (735 torr)(302 K)/(335 K) = 662.59 torr.

To know more about ideal gas law visit:

brainly.com/question/29405260

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5 0

1 year ago

Calculate the acid dissociation constant of a weak monoprotic acid if a 0.5M solution of this acid gives a hydrogen-ion concentr

RUDIKE [14]

Let the acid be HA.
The chemical formula for this acid will be the following:

$HA \rightleftharpoons H^{+}+A^{-}$

The formula for the <span>acid dissociation constant will be the following:

</span> $K_a= \dfrac{[H^+][A^-]}{[HA]}$
<span>
We know [H+]=0.0001 (it's given).
However, we must find [A-] and [HA] in order to solve for the constant.

We find that [A-]=[H+] by using a electroneutrality equation.
Also, we can create a concentration equation to find [HA].

</span> $0.5M=[A^-]+[HA]$
$[HA]=0.5M-[A^-]$
<span>
Now, we can find the acid dissociation constant.

</span> $K_a= \dfrac{[H^+][A^-]}{0.5M-[A^-]}$

$= \dfrac{0.0001*0.0001}{0.5-0.0001} = 2.0*10^{-8}$

4 0

3 years ago