The hybridization associated with the central atom of a molecule in which all the bond angles are 180° is ___

A 29.05 gram sample of cobalt is heated in the presence of excess oxygen. A metal oxide is formed with a mass of 40.88 g. Determ

deff fn [24]

The empirical formula of the oxide is Co₂O₃.

Step 1. Calculate the mass of oxygen

Your reaction is

Cobalt + oxygen ⟶ cobalt oxide

29.05 g + x g ⟶ 40.88 g

According to the Law of Conservation of Mass, the total mass of the reactants must equal the total mass of the products. Thus,

29.05 g + x g ⟶ 40.88 g

x = 40.88 – 29.05 = 11.83

Step 2. Calculate the moles of each element

The empirical formula is the simplest whole-number ratio of atoms in a compound.

The ratio of atoms is the same as the ratio of moles.

So, our job is to calculate the molar ratio of Co to O.

Moles of Co = 29.05 g Co × (1 mol Co /(58.93 g Co) = 0.492 96 mol Co

Moles of O = 11.83 g O × (1 mol O/16.00 g O) = 0.739 38 mol O

Step 3. Calculate the molar ratio of the elements

Divide each number by the smaller number of moles

Co:O = 0.429 26:0.739 38 = 1:1.4999

Step 4. Multiply each number by a factor that makes the ratio close to whole numbers

Multiply by 2. Then

Co:O = 2:2.998 ≈ 2:3

Step 5: Write the empirical formula

EF = Co₂O₃

4 0

3 years ago

Iron oxide and hydrogen react to form iron and water in the following chemical equation:

just olya [345]

Answer:

The answer to your question is 245.9 g of Fe₂O₃

Explanation:

Data

grams of Fe₂O₃ = ?

grams of Fe = 172 g

Balanced chemical reaction

Fe₂O₃ + 3H₂ ⇒ 2Fe + 3H₂O

Process

1.- Calculate the molar mass of of Iron Oxide and Iron

Fe₂O₃ = (2 x 56) + (3 x 16) = 112 + 48 = 160 g

2Fe = 2 x 56 = 112 g

2.- Use proportions and cross multiplication to solve this problem

160 g of Fe₂O₃ --------------- 112 g of Fe

x ---------------- 172 g of Fe

x = (172 x 160)/112

x = 27520/112

x = 245.9 g of Fe₂O₃

7 0

3 years ago

How would you describe the jumping pattern of the green frog bellow?

Roman55 [17]

Answer:

I would describe the jumping pattern of the green frog bellow as triangular or random it depend on you P.O.V.

8 0

3 years ago

In a titration experiment, hcl and lioh solutions were used. the initial volume of hcl was 1.25ml and lioh was 2.65 ml. the fina

aliya0001 [1]

Answer is: the molarity of HCl is 0.097 M.
Chemical reaction: LiOH + HCl → LiCl + H₂O.
V(HCl) = 13.60 mL - 1.25 mL = 12.35 mL.
V(LiOH) = 11.20 mL - 2.65 mL = 8.55 mL.
c(LiOH) = 0.140 M.
From chemical reaction: n(LiOH) : n(HCl) = 1 : 1.
c(HCl) · V(HCl) = c(LiOH) · V(LiOH).
c(HCl) = 8.55 mL · 0.140 M / 12.35 mL.
c(LiOH) = 0.097 M.

8 0

3 years ago

Draw the alkane formed when 4,5,5-trimethyl-1-hexyne is treated with two equivalents of hbr.

AveGali [126]

<h3>Answer:</h3>

The Alkane formed is 5,5-dibromo-2,2,3-trimethylhexane. as shown below in attached scheme (Green Color).

<h3>Explanation:</h3>

Alkynes like Alkenes undergo Electrophillic Addition Reactions. The reaction given is a two step reaction. In step 1, the Alkyne adds first equivalent of HBr obeying Markovnikov's rule (i.e. Bromine will add to carbon containing less number of hydrogen atoms) and forms 2-bromo-4,5,5-trimethylhex-1-ene. In step 2, the alkene formed in first step (2-bromo-4,5,5-trimethylhex-1-ene) undergoes addition reaction with the second equivalent of HBr via Markovnikov's rule to produce 5,5-dibromo-2,2,3-trimethylhexane.

The scheme is attached below, Blue color is assigned to starting Alkyne, Red color is assigned to intermediate Alkene and Green color is assigned to product Alkane respectively.

3 0

3 years ago

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The hybridization associated with the central atom of a molecule in which all the bond angles are 180° is ____.