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Anna007 [38]
4 years ago
13

The hybridization associated with the central atom of a molecule in which all the bond angles are 180° is ____.

Chemistry
1 answer:
enot [183]4 years ago
7 0

Answer:

Sp hybrid

Explanation:

Sp is linear I n shape

You might be interested in
Is hc2h3o2 quadraprotic?
agasfer [191]
No it isn’t.
do u mean quadratic either way it’s isn’t.
sorry for not much help xox
8 0
3 years ago
4. Assuming the reaction below is at equilibrium, which of the following changes will drive the reaction to the left? C(s) + O2(
shepuryov [24]

Answer:

Increasing temperature

Explanation:

C(s) + O_2(g) \leftrightharpoons CO_2(g)

Enthalpy of the reaction = -393.5 kJ/mol

Negative sign implies that reaction is exothermic.

Effect of change in reaction condition is explained by Le chateliers principle.

According to Le chateliers principle, if the reaction conditions of a reversible reaction in a state of dynamic equilibirum is changed, the reaction will move in a direction to counteract the change.

1. Increasing the temperature

Forward reaction is exothermic that means temperature increases in forward direction. Backward reaction will be endothermic and so there is decrease in temperature in backward direction or in left direction.

On increasing temperature, reaction will be move in direction to counteract the increased temperature, therefore reaction will move in left direction.

2. Adding O2

If O2 is added, then reaction will move in a direction in which its get consumed. So, reaction will move in forward direction or in right direction.

3. Removing C (s)

Le Chatelier's principle does not apply on solids, so removal of C(s) does not affect the equilibrium.

4 0
4 years ago
Read 2 more answers
6. The graph below shows the heating curve for ethanol (from –200C to 150C). Calculate the amount of heat (kJ) required for each
Kazeer [188]

This problem is providing the heating curve of ethanol showing relevant data such as the initial and final temperature, melting and boiling points, enthalpies of fusion and vaporization and specific heat of solid, liquid and gaseous ethanol, so that the overall heat is required and found to be 1.758 kJ according to:

<h3>Heating curves:</h3>

In chemistry, we widely use heating curves in order to figure out the required heat to take a substance from a temperature to another. This process may involve sensible heat and latent heat, when increasing or decreasing the temperature and changing the phase, respectively.

Thus, since ethanol starts off solid and end up being a vapor, we will find five types of heat, three of them related to the heating-up of ethanol, firstly solid, next liquid and then vapor, and the other two to its fusion and vaporization as shown below:

Q_T=Q_1+Q_2+Q_3+Q_4+Q_5

Hence, we begin by calculating each heat as follows, considering 1 g of ethanol is equivalent to 0.0217 mol:

Q_1=0.0217mol*111.5\frac{J}{mol*\°C}[(-114.1\°C)-(-200\°C)] *\frac{1kJ}{1000J} =0.208kJ\\&#10;\\&#10;Q_2=0.0217mol*4.9\frac{kJ}{mol} =0.106kJ\\&#10;\\&#10;Q_3=0.0217mol*112.4\frac{J}{mol*\°C}[(78.4\°C)-(-114.1\°C)] *\frac{1kJ}{1000J} =0.470kJ\\&#10;\\&#10;Q_4=0.0217mol*38.6\frac{kJ}{mol} =0.838kJ\\&#10;\\&#10;Q_5=0.0217mol*87.5\frac{J}{mol*\°C}[(150\°C)-(78.4\°C)] *\frac{1kJ}{1000J} =0.136kJ

Finally, we add them up to get the result:

Q_T=0.208kJ+0.106kJ+0.470kJ+0.838kJ+0.136kJ\\&#10;\\&#10;Q_T=1.758kJ

Learn more about heating curves: brainly.com/question/10481356

7 0
2 years ago
What is most likely to occur when jagged edges of rock plates grind past each other?
Ludmilka [50]

Answer:

The most likely to occur when jagged edges of rock plates grind past each other is the presence of a high degree of frictional force.

This may cause the rocks to be broken down into smaller particles.

It also implies that the energy necessary for further disintegration and movement of rocks is stored up.

7 0
3 years ago
Explain why quartz, SiO2(s), does not spontaneously decompose into silicon and oxygen at 25 °C in the reaction: SiO2 (s) → Si(s)
elixir [45]

Answer:

ΔH > O and ΔH > TΔS

Explanation:

When a reaction is non-spontaneous even though the standard entropy change of the reaction is large and positive the reason is the reaction is highly endothermic and dominates the term TΔS in the standard Gibbs free energy expression:

ΔG = ΔH-TΔS

Remember that for an endothermic  reaction to be spontaneous ΔG < 0 and this can occur only if the term TΔS is greater than ΔH. This is not the case for quartz which requires a good quantity of energy to overcome its crystaline 3D lattice in which  the oxygen are shared between 2 silicon atoms.

4 0
4 years ago
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