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liberstina [14]
3 years ago
13

What is the qualitative analysis of (nh4) 2co3 using NaOH, HCL, BaCL2, and AgNO3​

Chemistry
1 answer:
Pavlova-9 [17]3 years ago
8 0

Answer:

qualatatiev is fs-hj_jakakak

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For the diprotic weak acid h2a, ka1 = 3.2 × 10-6 and ka2 = 6.1 × 10-9. what is the ph of a 0.0650 m solution of h2a? what are th
Stolb23 [73]
Given:

Diprotic weak acid H2A:
 
Ka1 = 3.2 x 10^-6
Ka2 = 6.1 x 10^-9. 
Concentration = 0.0650 m 

Balanced chemical equation:

H2A ===> 2H+  + A2- 
0.0650       0        0
-x                2x       x
------------------------------
0.065 - x     2x      x

ka1 = 3.2 x 10^-6 = [2x]^2 * [x] / (0.065 - x)

solve for x and determine the concentration at equilibrium. 


5 0
3 years ago
The Development and Characterization of Carbon Nanofiber/Polylactic Acid Filament for Additively Manufactured Piezoresistive Sen
horrorfan [7]

Compared to carbon nanotube, carbon nanofiber (CNF) is a unique quasi-one-dimensional nanostructure with a lot of edges and flaws (CNT). Additionally, their low cost and wide availability make them a valuable nanomaterial for upcoming technology.

<h3>what are the development and characterization of Carbon Nanofiber for Additively Manufactured Piezo resistive Sensors?</h3>

In accordance with the semiconductor material's piezo resistive effect, diffusion resistance is used to manufacture piezo resistive sensors on substrates of semiconductor materials. The diffusion resistor is connected in the substrate in the form of a bridge, allowing the substrate to be employed directly as a measuring sensor element.

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5 0
1 year ago
How many mL of a 6 M NaOH stock solution is needed in order to prepare 500 mL of a 0.2 M NaOH solution?
WITCHER [35]

Answer:

The right answer is "16.67 mL".

Explanation:

Given:

Molarity of NaOH,

M_1=6 \ M

M_2=0.2 \ M

Volume of NaOH,

V_1=V \ mL

V_2=500 \ mL

As we know, the equation,

⇒ M_1V_1=M_2V_2

On putting the values, we get

⇒ 6\times V=0.2\times 500

⇒ 6\times V=100

⇒        V=\frac{100}{6}

⇒            =16.67 \ mL      

3 0
3 years ago
Calculation of ph from hydrogen ion concentration what is the ph of a solution that has an h1 concentration of (a) 1.75 3 1025 m
faltersainse [42]
<h2>Solutions:</h2>

<u>Case a:</u> Finding pH for [H⁺] = 1.75 × 10⁻⁵ mol/L :

As we know pH is given as,

                                  pH  = -log [H⁺]

Putting value,

                                  pH  = -log [1.75 x 10⁻⁵]

                                 pH =  4.75

<u>Case b:</u> Finding pH for [H⁺] = 6.50 × 10⁻¹⁰ mol/L :

As we know pH is given as,

                                  pH  = -log [H⁺]

Putting value,

                                  pH  = -log [6.50 × 10⁻¹⁰]

                                 pH =  9.18

<u>Case c:</u> Finding pH for [H⁺] = 1.0 × 10⁻⁴ mol/L :

As we know pH is given as,

                                  pH  = -log [H⁺]

Putting value,

                                  pH  = -log [1.0 × 10⁻⁴]

                                 pH =  4

<u>Case d:</u> Finding pH for [H⁺] = 1.50 × 10⁻⁵ mol/L :

As we know pH is given as,

                                  pH  = -log [H⁺]

Putting value,

                                  pH  = -log [1.50 × 10⁻⁵]

                                 pH =  4.82

7 0
3 years ago
Why is potassium less reactive than silver
Reika [66]
Because potassium is a gas that can evolve
3 0
3 years ago
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