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vesna_86 [32]
3 years ago
7

7+3√5/3+√5 - 7-3√5/3-√5​

Mathematics
1 answer:
Irina-Kira [14]3 years ago
4 0

Answer:

0

Step-by-step explanation:

We can write the equation in a simpler form so it doesn't look like a mess of numbers:

7+\frac{3\sqrt{5}}{3}+\sqrt{5} -7 -\frac{3\sqrt{5}}{3}-\sqrt{5}

Because we are just adding three terms together and then subtracting those exact terms, we have the answer as 0.

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A regular hexagon has an apothem measuring 14 cm and an approximate perimeter of 96 cm.
Mariulka [41]

ANSWER

672cm²

EXPLANATION

The area of a regular hexagon is given by the formula,

Area =  \frac{1}{2} ap

where a=14cm is the apothem and p=96cm is the perimeter of the regular hexagon.

We substitute the values into the formula,

Area =  \frac{1}{2}  \times 14 \times 96 {cm}^{2}

Area =672 {cm}^{2}

Therefore the approximate area of the hexagon is 672cm²

8 0
3 years ago
Read 2 more answers
If f left parenthesis x right parenthesis equals x squared minus 3 x plus 5 , then f left parenthesis 4 right parenthesis equals
lord [1]

Answer:

f(4) = 9

Step-by-step explanation:

f left parenthesis x right parenthesis equals x squared minus 3 x plus 5

f(x) = x² - 3x + 5

f left parenthesis 4 right parenthesis equals

f(4) =

f(x) = x² - 3x + 5

When x = 4

f(4) = 4² - 3(4) + 5

= 16 - 12 + 5

= 9

f(4) = 9

6 0
2 years ago
Se desconoce el número de alumnos que hay en una clase de repostería, cada alumno elaborará una galleta para cada compañero una
svetoff [14.1K]

Answer:

nsjsisjsjwisujssjnsmjsjsjsk jdjdjdjdjdjdjdjdjdjjsjsjxjdjdjnwbshxijandbvdjxkwksndndjjxisjsknendjjjxjzjzjwjowi kwhhdiwiqihiwhsiwjjxiwijidwjjwisisiakskdhbdvfhsiiwnwndhidisiwjehhhhhhhhhhhhhhhhhhhsisjwngxxuiajqnwnbdhdkalapoiwurnxkanammxkbsjjsisisowjncnchshauwoskdmfbcucusiwkkfhdhd

Step-by-step explanation:

jsjsjsjsjdjdjdjjdjddjjsksksskskwkjdjsisiwjjsjdbdbhsbsjsjsjjdiwiwiwjwhdnndbdjd

7 0
3 years ago
Use the Quadratic formula to find all real zeros of the 2nd degree polynomial
schepotkina [342]

Answer:

  x ∈ {-5, -1}

Step-by-step explanation:

Here's the solution using the quadratic formula:

x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}=\dfrac{-24\pm\sqrt{24^2-4\cdot 4\cdot 20}}{2\cdot 4}\\\\=\dfrac{-24\pm\sqrt{576-320}}{8}=\dfrac{-24\pm\sqrt{256}}{8}\\\\=\dfrac{-24\pm 16}{8}=-3\pm 2=\{-5,-1\}

The real zeros are -5 and -1.

_____

There are many ways to check your answer. One of them is to look at the given quadratic, which has no changes of sign in its coefficients. (They are all positive.) That means there can be no positive real roots, so already you know that x=0.5 won't work.

Also, the constant in the quadratic is the product of the roots, For your roots, their product is -7/4, so even multiplying by 4 (the leading coefficient in the given quadratic), you don't get anything like 20.

4 0
3 years ago
Prove 1 and 3 are supplementary
vovikov84 [41]

Answer:

Also question is, can 3 angles be supplementary? Remember, only a pair of angles can be supplementary. Sure, the three angles in a triangle may add up to 180 degrees, but there are three angles in a triangle, so they are not supplementary!

Step-by-step explanation:

6 0
2 years ago
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