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makkiz [27]
3 years ago
14

Evaluate the expression: 3c - 6d where c = 7 and d = -4

Mathematics
1 answer:
enyata [817]3 years ago
5 0

Answer:

45

Step-by-step explanation:

(3)(7)−(6)(−4)

=21−(6)(−4)

=21−(−24)

=45

You might be interested in
What is the answer to this inequality?<br> (x+7)&gt;80
Crank

Answer:

x > 73

Step-by-step explanation:

x+7 > 80

subtract 7 from both sides

x + 7 - 7 > 80 - 7

x > 73

-Chetan K

5 0
3 years ago
What number makes the sentence true?<br> 15 – 7 = 3+1
nasty-shy [4]

Answer:

4

Step-by-step explanation:

Although you didn't give me any answers to go with your problem, I am assuming that since 15-7 is 8, and 3 + 1 = 4, the answer should be 4. Now regarding if it is times, it would be x2. Because for times 2 would be 8. Overall the answer should be 4.

3 0
3 years ago
Tennis elbow is thought to be aggravated by the impact experienced when hitting the ball. The article "Forces on the Hand in the
Gnoma [55]

Answer:

Step-by-step explanation:

Hello!

The objective is to study whether there is a greater force after impacting on one- handed backhand drive in advanced tennis players than in intermediate tennis players.

Sample 1: Advanced tennis players

X₁: Force (N) on the hand just after impact on a one- handed backhand drive for an advanced tennis player.

n₁= 6

X[bar]₁= 40.29 N

S₁= 11.29

Sample 2: Intermediate players

X₂: Force (N) on the hand just after impact on a one- handed backhand drive for an intermediate tennis player.

n₂= 8

X[bar]₂= 21.40

S₂= 8.30

Assuming that both variables have a normal distribution and both population variances are equal, to compare these two populations is best to do so trough their population means using a t-test for independent samples.

If the force is greater for the advanced players than for the intermediate players, then you'd expect the population mean for the advanced players to be greater than the population mean for the intermediate players:

H₀: μ₁ ≤ μ₂

H₁: μ₁ > μ₂

α: 0.05

t= \frac{(X_[bar]_1-X[bar]_2)-(Mu_1-Mu_2)}{Sa\sqrt{\frac{1}{n_1} +\frac{1}{n_2} } } ~~t_{n_1+n_2-2}

Sa= \sqrt{\frac{(n_1-1)S_1^2+(n_2-1)S_2^2}{n_1+n_2-2} } = \sqrt{\frac{5*127.51+7*68.92}{6+8-2} }= 9.66

t_{H_0}= \frac{(40.29-21.40)-0}{9.66\sqrt{\frac{1}{6} +\frac{1}{8} } } = 3.62

Using the p-value approach, the decision rule is

If p-value ≤ α, reject the null hypothesis

If p-value > α, do not reject the null hypothesis

The p-value for this test is 0.00024, it is less than the level of significance, so the decision is to reject the null hypothesis.

This means that at a 5% significance level you can conclude that the average force experienced on the hand after a one-handed backhand drive for advanced players is greater than the average force experienced on the hand after a one-handed backhand drive for intermediate players.

I hope this helps!

3 0
4 years ago
At a school, 177 students play a sport. This is 60% of the students that go to the school. How many students are at the school?
TEA [102]

Answer:

the answer is 205

Step-by-step explanation:

%/100 X is/of  177 IS 60% of the students. so you put 60/100 and multiply 177/X  177X100=17700. Now divide that by 60 and you come up with 28.33.  This obviously is not the answer so you add 28 (does not round up to 29) to 177 and you get 205.

7 0
4 years ago
Calcute The Circumference of the circle
Sladkaya [172]

Answer:

depends on what the radius is

:)

Step-by-step explanation:

7 0
3 years ago
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