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svp [43]
3 years ago
10

Find the value of m. (-3/4)-⁴×(-3/4)-¹¹ = (-3/4)^m​

Mathematics
1 answer:
tatiyna3 years ago
4 0

Answer:

m = - 15

Step-by-step explanation:

Using the rule of exponents

a^{m} × a^{n} = a^{(m+n)} , then

(-\frac{3}{4}) ^{-4} × (-\frac{3}{4}) ^{-11} = (-\frac{3}{4}) ^{m} , that is

(-\frac{3}{4}) ^{(-4-11)} = (-\frac{3}{4}) ^{m}

(-\frac{3}{4}) ^{-15} = (-\frac{3}{4}) ^{m}

Equating exponents gives

m = - 15

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A study suggested that childrenbetween the ages of 6 and 11 in the US have anaverage weightof 74 lbs. with a standard deviation
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Answer:

The proportion of children in this age range between 70 lbs and 85 lbs is of 0.9306.

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

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The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

A study suggested that children between the ages of 6 and 11 in the US have an average weightof 74 lbs, with a standard deviation of 2.7 lbs.

This means that \mu = 74, \sigma = 2.7

What proportion of childrenin this age range between 70 lbs and 85 lbs.

This is the pvalue of Z when X = 85 subtracted by the pvalue of Z when X = 70. So

X = 85

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Z = \frac{70 - 74}{2.7}

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The proportion of children in this age range between 70 lbs and 85 lbs is of 0.9306.

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