Answer:
te mean is 5
median is 12
avarae is 6
Step-by-step explanation:
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Based on the distance of the pitcher's mound from the home plate, the path of the ball, and the height the ball was hit, the distance the outfielder threw the ball is C. 183.0 ft.
<h3>How far did the outfielder throw the ball?</h3>
Based on the shape of a mound, the law of cosines can be used.
The distance the ball was thrown by the outfielder can therefore be d.
Distance is:
d² = 60.5² + 226² - (2 x 60.5 x 226 x Cos(39))
d ²= 33,484.42ft
Then find the square root:
d = √33,484.42
= 182.9874
= 183 ft
Find out more solving for distance at brainly.com/question/10739348
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Answer: d) 0.9693
<u>Step-by-step explanation:</u>
refer to the z-table attached.
The table shows the percent from the MEAN. The percent below the mean is 50% so that needs to be added to the value in the table.
Look on the left side for 1.8 and the top for 0.07 (which is 1.87).
The value is 0.4693 --> add 0.5 to that value to get 0.9693.
Answer:
D. All real numbers
Step-by-step explanation:
The range of a function is all of the possible x-values (which is easiest to understand if you can view a graph), and the domain of a function is all possible y-values.
So, you could put any x-value into this function (and it would have a corresponding y-value)
The domain [y] is limited, but the range [x] is best described as all real numbers
(if it's hard to remember which is which, d comes before r alphabetically, and x comes before y alphabetically)