Given that JKLM is a rhombus and the length of diagonal KM=10 na d JL=24, the perimeter will be found as follows;
the length of one side of the rhombus will be given by Pythagorean theorem, the reason being at the point the diagonals intersect, they form a perpendicular angles;
thus
c^2=a^2+b^2
hence;
c^2=5^2+12^2
c^2=144+25
c^2=169
thus;
c=sqrt169
c=13 units;
thus the perimeter of the rhombus will be:
P=L+L+L+L
P=13+13+13+13
P=52 units
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Answer:
32 units^2
Step-by-step explanation:
Finding the width and the length:
One side = √[(-1 - (-1)^2 + (5 - (-3))^2]
= √(0 + 64)
= 8.
The adjacent side = √(9-9)^2 + (-3-5)^2
= 8.
Perimeter - 4 *8 = 32 units^2.
Answers:
5. 296
6. 479
7. 801
8. 920
9. $281
Step-by-step explanation:
For 5-8, you add the 2 numbers. Line up the numbers by their place value.
For 9, it says she starts with $233. She worked for 6 hours today. She makes $8 for every hour. First, you have to find how much she made today. 6 hrs times $8 for every hr is $48. In total, she has $281 because we added the amount she starts with, and the amount she earned today.
Henson's cost: 3x+y=203
Garcia's cost: 2x+3y=189
Step-by-step explanation:
Given,
Cost of each adult ticket = x dollars
Cost of 3 adult ticket = 3x
Cost of 2 adult ticket = 2x
Cost of each child ticket = y dollar
Cost of 3 child ticket = 3x
Henson's cost;
3 adult tickets + 1 child ticket = $203
3x+y=203
Garcia's cost;
2 adult tickets + 3 child tickets = $189
2x+3y=189
Henson's cost: 3x+y=203
Garcia's cost: 2x+3y=189
Keywords: linear equation, addition
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