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Alex777 [14]
3 years ago
6

What is the Volume of a hexagonal pyramid shown if the hexagon has a side length of 4 inches and the height of the pyramid is 12

inches?
Mathematics
1 answer:
SIZIF [17.4K]3 years ago
4 0

Answer:

  • 166.24 in³

Step-by-step explanation:

<u>Volume formula:</u>

  • V = 1/3 Bh, B-base area, h- height

<u>Base area:</u>

  • B = 3√3a² / 2 = 3√3*4² / 2 = 41.57 in (rounded)

<u>Volume:</u>

  • V = 1/3*41.56*12 = 166.24 in³

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Does anyone understand this?. I also have to show my work.
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Answer:

Ans A). The graph is shown.

Ans B). 18.3333 C temperature when F is 65 temperature

Ans C). 32 F when the line crosses the horizontal axis

Ans D). Slope of line C=\frac{5}{9}(F -32) is \frac{5}{9}

Step-by-step explanation:

Given equation is C=\frac{5}{9}(F -32)

Ans A).

For the table,

Take the four value of F as 32,41,50,59.

For F = 32.

The value of C is

C=\frac{5}{9}(F -32)

C=\frac{5}{9}(32 -32)

C=0.

For F = 41.

The value of C is

C=\frac{5}{9}(F -32)

C=\frac{5}{9}(41 -32)

C=05

For F = 50.

The value of C is

C=\frac{5}{9}(F -32)

C=\frac{5}{9}(50 -32)

C=10

For F = 59.

The value of C is

C=\frac{5}{9}(F -32)

C=\frac{5}{9}(32 -32)

C=15

<em>Note: The figure shows a graph of given equation with points.</em>

Ans B). Estimate temperature in C when the temperature in F is 65

For F = 65.

The value of C is

C=\frac{5}{9}(F -32)

C=\frac{5}{9}(32 -32)

<em>C=18.333333.</em>

Ans C). At what temperature, graph lien cross the horizontal axis

When the line crosses the horizontal axis, C=0

Therefore,

C=\frac{5}{9}(F -32)

0=\frac{5}{9}(F -32)

0=(F -32)

F=32 Temperature.

Ans D). Slope of the line C=\frac{5}{9}(F -32)

The slope of line is given by s= \frac{Y1-Y2}{X1-X2}

Take points from the table of answer A.

let (32,0) and (41,5) using for slope.

s= \frac{Y1-Y2}{X1-X2}

s= \frac{0-5}{32-41}

s= \frac{5}{9}

Slope of line C=\frac{5}{9}(F -32) is \frac{5}{9}

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3 years ago
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