Answer:
d=4
Step-by-step explanation:
Agency 1:
Total cost of renting a car=24.50d + 15.99
Agency 2:
Total cost of renting a car=27.50d + 3.99
Where, d=No. of days of renting the car
Which equation could be used to find the number of days, d, at which the rental fee is the same for both agencies?
The equation is by equating agency 1 and agency 2 equation
24.50d + 15.99 = 27.50d + 3.99
Collect like terms
24.50d - 27.50d = 3.99 - 15.99
-3d = -12
Divide both sides by -3
d= -12 / -3
=4
d=4
Check
Agency 1:
24.50d + 15.99
= 24.50(4) + 15.99
= 98 + 15.99
= 113.99
Agency 2:
27.50d + 3.99
= 27.50(4) + 3.99
= 110 + 3.99
= 133.99
Answer:
I think it would be D
Step-by-step explanation:
20 x 3 = 60 60+35= 95 20/4 = 5
<h2><u>Q</u><u>u</u><u>e</u><u>s</u><u>t</u><u>i</u><u>o</u><u>n</u>:-</h2>
What is the value of this expression when c = -4 and d = 10 ? 
(c³ + d²)
<h2><u>A</u><u>n</u><u>s</u><u>w</u><u>e</u><u>r</u>:-</h2>
<h3>Given:-</h3>
(c³ + d²) where c = -4 and d = 10
<h3>To Find:-</h3>
The value of the expression (c³ + d²)
<h2>Solution:-</h2>
(c³ + d²) [Given expression]
Now, putting the value of c = -4 and d = 10 , we get,
{ (-4)³ + (10)² }
( -64 + 100 )
( 36 )
× 36
I think it’s 4 pairs cause 4 pants is less than 5 shoes and 8 is bigger than 4
Answer:
Step-by-step explanation:
Here are the steps to follow when solving absolute value inequalities:
Isolate the absolute value expression on the left side of the inequality.
If the number on the other side of the inequality sign is negative, your equation either has no solution or all real numbers as solutions.
If your problem has a greater than sign (your problem now says that an absolute value is greater than a number), then set up an "or" compound inequality that looks like this:
(quantity inside absolute value) < -(number on other side)
OR
(quantity inside absolute value) > (number on other side)
The same setup is used for a ³ sign.
If your absolute value is less than a number, then set up a three-part compound inequality that looks like this:
-(number on other side) < (quantity inside absolute value) < (number on other side)
The same setup is used for a £ sign
