3 years ago

The answer is. 90 and 80 on I-Ready hope this helped! :)

Mathematics

1 answer:

goldenfox [79]3 years ago

7 0

you did a question not an answer pal sorry

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A line passes through the points (2,21) and (8,27). Write a linear function rule in terms of x and y for

tatiyna

We have two points so we can find the gradient using y1-y2/x1-x2
gradient = 21-27/2-8
= 1
we know the form for any linear equation is y = mx + c
we have m and a point so we can substitute in point (2,21) to find c
21 = 1 x 2 + c
c = 19
therefore, the equation is y = x + 19

6 0

2 years ago

Read 2 more answers

Please help me !!!

kati45 [8]

$23)~75r^2-48=3(25r^2-16)=3(5r-4)(5r+4)\\\\
24)~45x^2-5=5(9x^2-1)=5(3x-1)(3x+1)\\\\
25)~m^3n-mn^3=mn(m^2-n^2)=mn(m-n)(m+n)\\\\
26)~6a^3-24ab^2=6a(a^2-4b^2)=6a(a-2b)(a+2b)\\\\
27)~3x^2+15x-72=3(x^2+5x-24)=3(x-3)(x+8)\\\\
28)~2m^2-4m+2=2(m^2-2m+1)=2(m-1)^2\\\\
29)~x^3+9x^2-52x=x(x^2+9x-52)=x(x-4)(x+13)\\\\
30)~4y^3+4y^2-120y=4y(y^2+y-30)=4y(y-5)(y+6)$