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Dmitry [639]
3 years ago
8

16x³y²z-8x²y³z² factorise it​

Mathematics
1 answer:
Tju [1.3M]3 years ago
8 0

8x²y²z(2x-yz)

Answer:

Solution given;

16x³y²z-8x²y³z²

let look what is common there;

2*8*x²*x*y²*z-8*x²*y²*y*z*z

over here 8x²y²z is common

take common and keep other remaining on bracket

<u>8x²y²z(2x-yz)</u>

<u>In a simple way </u><u>8x²y²z(2x-yz)</u><u> </u> is a factorise form of 16x³y²z-8x²y³z²

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