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Vesna [10]
3 years ago
5

DESDE LA PARTE ALTA DE UN MURO DE 8M DE ALTURA SE OBSERVA LAS PARTE BAJA Y ALTA DE UN EDIFICIO CON ANGULOS DE ELEVACION Y DEPRES

ION DE 37 Y 45 RESPECTIVAMENTE. CALCULA LA ALTURA DEL EDIFICIO A.18 B.14 C.12 D.24 E.16

Mathematics
1 answer:
d1i1m1o1n [39]3 years ago
3 0

Answer:

The height of the building is approximately 18 meters.

Step-by-step explanation:

The question is:

FROM THE HIGH PART OF A WALL OF 8M HEIGHT, YOU CAN SEE THE LOW AND HIGH PART OF A BUILDING WITH ELEVATION AND DEPRESSION ANGLES OF 37° AND 45° RESPECTIVELY. CALCULATE THE HEIGHT OF THE BUILDING A.18 B.14 C.12 D.24 E.16

Solution:

Consider the diagram below.

Consider the triangle ABC.

Compute the value of <em>y</em> as follows:

tan\ 37^{o}=\frac{AB}{BC}

  0.754=\frac{8}{y}

        y=\frac{8}{0.754}

           =10.61\\\approx 11

Thus, the length of side AD is also 11 meters.

Now consider the triangle AED.

Compute the value of <em>x</em> as follows:

tan\ 45^{o}=\frac{AE}{ED}

        1=\frac{11}{x}

        x=11

Then the height of the building is:

\text{Height of the Building}=x+8

                                 =11+8\\=19

From the options provided it can be concluded that the height of the building is approximately 18 meters.

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If someone could work out the first half of the problem and explain that would be great!
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Step-by-step explanation:

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Select all ratios equivalent to 15:5.<br> 9:3<br> 6:2<br> 3:1
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Answer:

All three.

Step-by-step explanation:

All three of these ratios are equivalent to 15:5. Here's how:

Let's look at the first ratio, 9:3. Did you notice something common? 3 x 3 = 9. 9/3 = 3. 5 x 3 = 15. 15/3 = 5. Both of these numbers are divisible by 3,  so these ratios are equivalent.

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