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notka56 [123]
3 years ago
9

Each year, roughly `10^{6\ }`computer programmers each make about $`10^{5}`. How much money is this all together? Express your a

nswer both as a power of 10 and as a dollar amount.
Mathematics
1 answer:
mina [271]3 years ago
3 0

Answer:

69

Step-by-step explanation:

69e420+60532598423534543

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SOMEONE PLZZZZ HELP THIS IS DUE SOON!!! :)
Lelu [443]

Answer:

im stumped.

Step-by-step explanation:

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3 years ago
HELP PLEASE!!!
Marina CMI [18]

Answer:

The maximum profit of $  10277.32____ can be made when the selling price of the dog food is set to $ _34___ per bag.

Step-by-step explanation:

Profit = Revenue - Cost

P(x) = R(x) -C(x)

       = -31.72x^2 + 2,030x -( -126.96x + 26,391)

Distribute the minus sign

       = -31.72x^2 + 2,030x+126.96x - 26,391

 Combine like terms

      =   -31.72 x^2 + 2156.96 x - 26391

This is a parabola.  It is facing downwards.  The maximum profits is at the vertex ( where the max is)

vertex = h = -b/2a = -(2156.96)/(2*-31.72) = -2156.96/-63.44=34

Evaluate P(x) at x=34 to determine the profit

P(34) =  -31.72 (34)^2 + 2156.96 (34) - 26391

          -36668.32+73336.64-26391

          10277.32

8 0
3 years ago
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(who are you riddle) I'm smaller than 24. I am a common multiple of 7 and 3
sergiy2304 [10]
I think the answer is 21.
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3 years ago
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A zoologist is studying four very closely related feline species. She wishes to compare their gestation periods. An observationa
diamong [38]

Answer:

p_v= 0.01

Since the significance level is 0.05 we see that pv so we have enough evidence to reject the null hypothesis. And the best conclusion for this case would be:

b. at least some, but not all, of the gestation periods across all four species are the same

Because is only to identify if AT LEAST one mean is different, NOT to conclude that the all the means are different.

Step-by-step explanation:

Previous concepts

Analysis of variance (ANOVA) "is used to analyze the differences among group means in a sample".  

The sum of squares "is the sum of the square of variation, where variation is defined as the spread between each individual value and the grand mean"  

Solution to the problem

The hypothesis for this case are:

Null hypothesis: \mu_{A}=\mu_{B}=\mu_{C}= \mu_D

Alternative hypothesis: Not all the means are equal \mu_{i}\neq \mu_{j}, i,j=A,B,C,D

In order to find the mean square between treatments (MSTR), we need to find first the sum of squares and the degrees of freedom.

If we assume that we have p=4 groups and on each group from j=1,\dots,p we have n_j individuals on each group we can define the following formulas of variation:  

SS_{total}=\sum_{j=1}^p \sum_{i=1}^{n_j} (x_{ij}-\bar x)^2  

SS_{between}=SS_{model}=\sum_{j=1}^p n_j (\bar x_{j}-\bar x)^2  

SS_{within}=SS_{error}=\sum_{j=1}^p \sum_{i=1}^{n_j} (x_{ij}-\bar x_j)^2  

And we have this property  

SST=SS_{between}+SS_{within}  

And in order to test this hypothesis we need to ue an F statistic and for this case the p value calculated is

p_v= 0.01

Since the significance level is 0.05 we see that pv so we have enough evidence to reject the null hypothesis. And the best conclusion for this case would be:

b. at least some, but not all, of the gestation periods across all four species are the same

Because is only to identify if AT LEAST one mean is different NOT to conclude that the all the means are different.

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3 years ago
The Tennessee Titans scored 22 points in week 5 and 35 points in week 6. Find the percent of increase.
Shalnov [3]

Answer:

59.09%

Step-by-step explanation:

35-22=13

13/2= .59090909=59.09%

3 0
3 years ago
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