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Alenkasestr [34]
3 years ago
5

ANSWER #1 AND #2 FOR MEEE PLLEEEAAASSEEEe

Mathematics
2 answers:
Zina [86]3 years ago
8 0

the answer for #1 would be 9.9919 × 10^4

the answer for #2 would be B.

Oxana [17]3 years ago
5 0

Answer:

1st 9.919x10^4 2nd a

Step-by-step explanation:

sorry if I got this wrong

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Help me with this one!
Natasha_Volkova [10]

Answer:

It’s A

Step-by-step explanation:

Cuz it’s just the numbers are replaced in different places but when u multiply u get the same ans ig

6 0
3 years ago
It is known that the distance in metres through which a body falls freely varies directly as the square of the time taken. If a
erma4kov [3.2K]

Answer:

125 meters

Step-by-step explanation:

Let distance = d and time is t

Using the variation;

d = k t^2

So let’s us get k

80 = k * 4*2

16k = 80

k = 80/16 = 5

So for 5 seconds, the distance would be;

d = 5 * 5^2

d = 125 meters

4 0
4 years ago
Explain the difference between equilateral and equiangular :) ​
mixas84 [53]

An equilateral polygon has congruent sides, like a rhombus.

An equiangular polygon has congruent interior angles, like a rectangle.

In other words: Equilateral doesn't necessarily have congruent INTERIOR angles while equiangular does have/need congruent interior angles.

4 0
3 years ago
A small cylindrical has a diameter of 18mm and a height 12mm. Determine the minimum surface area of a box that can hold a row of
dimaraw [331]

Answer:

The surface are of a box = 1186.92 mm²  

Step-by-step explanation:

Given in question as :

Diameter of cylinder = 18 mm

The height of cylinder = 12 mm

The surface area of cylinder = ( 2×\pi×r×h) + (2×\pi×r²)

where R is the radius , R = \frac{Diameter}{2}  = \frac{18}{2}

Or Radius r = 9 mm

Or, The surface area of cylinder= ( 2×\pi×9×12) + 2×\pi×(9)²)

Or , The surface area of cylinder=(678.24) + (508.68)

Or ,The surface area of cylinder= 1186.92 mm²

Hence the surface are of a box = 1186.92 mm²     Answer

5 0
3 years ago
(2x + 3)" and solve for x
Novosadov [1.4K]

Answer:

2x−3=x

Move all terms containing x

to the left side of the equation.

Subtract x

from both sides of the equation.

2x−3−x=0

Subtract x

from 2x

x−3=0

Add 3

to both sides of the equation.

x=3

7 0
3 years ago
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