
Divide both sides by
:

Substitute
, so that
.

Multiply both sides by
:

The left side can be condensed into the derivative of a product.

Integrate both sides to get

Solve for
:

Solve for
:

![\implies\boxed{y(x)=\sqrt[3]{\dfrac14x^2e^x(2\ln x-1)+Ce^x}}](https://tex.z-dn.net/?f=%5Cimplies%5Cboxed%7By%28x%29%3D%5Csqrt%5B3%5D%7B%5Cdfrac14x%5E2e%5Ex%282%5Cln%20x-1%29%2BCe%5Ex%7D%7D)
Answer:
b = 5
Step-by-step explanation:
Calculate m using the slope formula
m = (y₂ - y₁ ) / (x₂ - x₁ )
with (x₁, y₁ ) = C(1, 3) and (x₂, y₂ ) = D(4, - 3)
m =
=
= - 2, hence
y = - 2x + b ← is the partial equation of the line
To find b substitute either of the 2 points into the partial equation
Using (1, 3), then
3 = - 2 + b ⇒ b = 3 + 2 = 5
Answer:
Period of the function is 4π
Step-by-step explanation:
Given is a graph:
It oscillates between -1 and +1
The graph shows angles on x axis and trig values on y axis.
The graph has value +1 when x=0 and reaches minimum -1 when x =2pi and again reaches y=1 when x =4 π
Thus we find that this is a periodic function with amplitude 1 and phase shift 0 and period 4π
So we get the period of the trignometric funciton is 4π
So option 1 is right
Verify:
Given function is y = cos
Since parent function y =cosx has a period of 2pi, we have
here period = 2pi/coefficient of x in cos
=2pi/(1/2)
=4pi
Answer:
D
Step-by-step explanation:
x,y 2,3 just trust me good sir