3 years ago

Find the greatest common factor of 11 m² and 4y^3.

1 answer:

5 0

Answer:

No common factor. Answered by Gauthmath

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Artemon [7]

Answer:

Step-by-step explanation:

If each day equal chance then p = Prob that a person is borne on a particular day = 1/365

Each person is independent of the other and there are two outcomes either borne in July or not

p = prob for one person not borne in July = (365-31)/365 = 334/365

a)Hence prob that no one from n people borne in July = $(\frac{334}{365} )^n$

b) p = prob of any one borne in July or Aug = $\frac{(31+31) }{365} =\frac{62}{365}$ =0.1698

X- no of people borne in July or Aug

n =15

P(X>=2) = $15C2 (0.1698)^2*(1-0.1698)^{13} +15C3 (0.1698)^3*(1-0.1698)^{12} +...+15C15 (0.1698)^{15}$

=0.7505

3 0

2 years ago

dangina [55]

Set the function up in integral form and evaluate to find the integral.
F(x)=F(x)=12x2−ln(|x|)−1x2+C

3 0

3 years ago

Ymorist [56]

.45x+.55x=200
Combine like terms
1x=200
So x is 100

Or you can do 45%+55%=100%
And 100% of 200 is 200

8 0

3 years ago

Debora [2.8K]

Answer:

2/5

Step-by-step explanation:

7 0

2 years ago

Serggg [28]

Creo que es A si no es porfavor dime.

6 0

2 years ago