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Hoochie [10]
2 years ago
8

PLEASE ANSWER ASAP FOR BRAINLEST!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! Please also show with work!

Mathematics
1 answer:
slavikrds [6]2 years ago
7 0

Answer:

66cm²

Step-by-step explanation:

Okay so lets start by breaking this down and writing a smiple equation to find the area.

We know that the N's are the same size. To make it easier we can turn them to a square/rectangle. I think it would be easist to move the bottem N's to the top. (look at the pic attached to see what i mean)

Lets start by finding the area of the top rectangle. We need to divide 8 by 2 to find the height.

a = b * h

a = 12 * 4 = 48(area of top rectangle)

a(of m) = 4.5 * 4 = 18

area of the whole thing:

a = 48 + 18 = 66

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Greeley [361]

Answer:

3

Step-by-step explanation:

plz mark brainliest

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3 years ago
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The roots of $3x^2 - 4x + 15 = 0$ are the same as the roots of $x^2 + bx + c = 0,$ for some constants $b$ and $c.$ Find the orde
Akimi4 [234]

we are given

quadratic equation as

3x^2-4x+15=0

now, we can find b and c from

x^2+bx+c=0

we can see that coefficient of x^2 is 1

so, we will have to make coefficient x^2 as 1

so, we divide both sides by 3

3x^2-4x+15=0

\frac{3x^2-4x+15}{3}= \frac{0}{3}

\frac{3x^2}{3}-\frac{4x}{3}+\frac{15}{3}= \frac{0}{3}

now, we can simplify it

x^2-\frac{4}{3}x+5= 0

now, we can compare it with

x^2+bx+c=0

we get

b=-\frac{4}{3}

c=5

so, we get order pair as

(b,c)=(-\frac{4}{3} , 5)..............Answer

6 0
3 years ago
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What expression shows the relationship between the value of any term and n, its position in the sequence for the given sequence?
mafiozo [28]
Answer: -3n-2. 

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8 0
2 years ago
50 POINTS IF YOU ANSWER!
MatroZZZ [7]

Answer:

2 m/s

Step-by-step explanation:

60*5=300

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5 0
2 years ago
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De moirve's <br> (√3-i ÷ √3+i)^6 = 1
bulgar [2K]

(√3 - <em>i </em>) / (√3 + <em>i</em> ) × (√3 - <em>i</em> ) / (√3 - <em>i</em> ) = (√3 - <em>i</em> )² / ((√3)² - <em>i</em> ²)

… = ((√3)² - 2√3 <em>i</em> + <em>i</em> ²) / (3 - <em>i</em> ²)

… = (3 - 2√3 <em>i</em> - 1) / (3 - (-1))

… = (2 - 2√3 <em>i</em> ) / 4

… = 1/2 - √3/2 <em>i</em>

… = √((1/2)² + (-√3/2)²) exp(<em>i</em> arctan((-√3/2)/(1/2))

… = exp(<em>i</em> arctan(-√3))

… = exp(-<em>i</em> arctan(√3))

… = exp(-<em>iπ</em>/3)

By DeMoivre's theorem,

[(√3 - <em>i </em>) / (√3 + <em>i</em> )]⁶ = exp(-6<em>iπ</em>/3) = exp(-2<em>iπ</em>) = 1

7 0
3 years ago
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