We are given the function
F(x) = 9 sinx + cot x
We need to take the first derivative of the given function so,
F' (x) = 9 cos x - csc² x
Next, we equate the first derivative of the function to 0 and solve for the values of x
0 = 9 cos x - csc² x
Solving for x
x = 2.04
Picking out an arbitrary value between 2.04 and π, say 3 and substituting in F(x)
F(3) = 9 sin 3 + cot 3 = 19.55
Therefore, the interval where the function is increasing is from 2.04 to π
Consequently, the interval where the function is decreasing is from -π to 2.04<span />
Answer:
y= 2/5-1
Step-by-step explanation:
You get the 2/5 because you go 2 to the right and go 5 up, the -1 is because the x-int is at -1.
Answer:
739,266
Step-by-step explanation:
1) We calculate the volume of a metal bar (without the hole).
volume=area of hexagon x length
area of hexagon=(3√3 Side²)/2=(3√3(60 cm)²) / 2=9353.07 cm²
9353.07 cm²=9353.07 cm²(1 m² / 10000 cm²)=0.935 m²
Volume=(0.935 m²)(2 m)=1.871 m³
2) we calculate the volume of the parallelepiped
Volume of a parallelepiped= area of the section x length
area of the section=side²=(40 cm)²=1600 cm²
1600 cm²=(1600 cm²)(1 m² / 10000 cm²=0.16 m²
Volume of a parallelepiped=(0.16 m²)(2 m)=0.32 m³
3) we calculate the volume of a metal hollow bar:
volume of a metal hollow bar=volume of a metal bar - volume of a parallelepiped
Volume of a metal hollow bar=1.871 m³ - 0.32 m³=1.551 m³
4) we calculate the mass of the metal bar
density=mass/ volume ⇒ mass=density *volume
Data:
density=8.10³ kg/m³
volume=1.551 m³
mass=(8x10³ Kg/m³ )12. * (1.551 m³)=12.408x10³ Kg
answer: The mas of the metal bar is 12.408x10³ kg or 12408 kg
