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3 years ago

Given that the ka for hocl is 3.5 × 10–8, calculate the k value for the reaction of hocl with oh–.

2 answers:

6 0

Following reaction is involved in above system
HOCl(aq) ↔ H+(aq) + OCl-(aq)
OCl-(aq) + H2O(l) ↔ HOCl(aq) + OH-(aq)

Now, if the system is obeys 1st order kinetics we have
K = [OCl-][H+]/[HOCl] ............. (1)
∴ [HOCl-] / [OCl-] = [H+] (1 / 3.0 * 10-8) ............. (2)

and now considering that system is obeying 2nd order kinetics, we have
K = [OH-][HOCl-] / [OCl-] ................. (3)
Subs 2 in 3 we get
K = [OH-][H+] (1 / 3.0 * 10-8)
we know that, [OH-][H+] = 10-14

∴K = 3.3 * 10-7

Thus, correct answer is e i.e none of these

valina [46]3 years ago

5 0

Answer:

3.5 * 10^6

Explanation:

In this question, we are asked to calculate the the k-value for the reaction of HOCl with OH- given Ka value for HOCl

Firstly, we write the dissociation equation for HOCl

This is as follows;

HOCl ——> H+ + OCl-

Now, we write an expression for Ka

Ka = [H+][OCl-]/HOCl = 3.5 * 10^-8

Now, we write an equation for the reaction of HOCl and OH- ;

HOCl + OH- —-> OCl- + H2O(l)

The K value expression for this can be written as;

K = [OCl-]/[HOCl][OH-]

= [H+][OCl-]/[HOCl] * [1/[H+][OH-]

= ka * 1/Kw = 3.5 * 10^-8 /(1 * 10^-14) = 3.5 * 10^6

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46.6 grams of mercury II sulfate (HgSO4) reacts with an excess of sodium Chloride (NaCl). How many grams of mercury II chloride

slega [8]

Answer:

$m_{HgCl_2}=42.7gHgCl_2$

Explanation:

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In this case, the undergoing chemical reaction is:

$HgSO_4+2NaCl\rightarrow HgCl_2+Na_2SO_4$

In such a way, the mercury II sulfate (molar mass 296.65g/mol) is in a 1:1 molar ratio with the mercury II chloride (molar mass 271.52g/mol), for that reason the stoichiometry to find mass in grams of mercury II chloride turns out:

$m_{HgCl_2}=46.6gHgSO_4*\frac{1molHgSO_4}{296.65 gHgSO_4}*\frac{1molHgCl_2}{1molHgSO_4} *\frac{271.52gHgCl_2}{1molHgCl_2} \\\\m_{HgCl_2}=42.7gHgCl_2$

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3 0

3 years ago

2. What pressure is required to compress 196.0 L of air at 1.00 atmosphere into a cylinder

damaskus [11]

Answer:

Explanation:

The required pressure can be found by using the formula for Boyle's law which is

$P_2 = \frac{P_1V_1}{V_2} \\$

where

P1 is the initial pressure

P2 is the final pressure

V1 is the initial volume

V2 is the final volume

From the question we have

$P_2 = \frac{1 \times 196}{26} = \frac{196}{26} \\ = 7.538461...$

We have the final answer as

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3 0

2 years ago

A gas quickly expands in an isolated environment. During the process, the gas exchanges no heat with its surroundings. The proce

AysviL [449]

Answer:

e. adiabatic process

Explanation:

Adiabatic process -

In the thermodynamic system , an adiabatic process is the one which involves no transfer of mass or heat of the substance , is referred to adiabatic process.

In this process , the temperature need not be constant ,

But only the heat is transferred into or out of the system .

Hence, from the given information of the question,.

The correct option is e. adiabatic process .

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4 years ago

Hydrogenation reactions, in which H2 and an "unsaturated" organic compound combine, are used in the food, fuel, and polymer indu

ddd [48]

Answer: The amount of heat released is 56 MJ.

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Given mass of $C_2H_6$ = 12 kg = 12000 g (Conversion factor: 1 kg = 1000 g)

Molar mass of $C_2H_6$ = 30 g/mol

Putting values in above equation, we get:

$\text{Moles of }C_2H_6=\frac{12000g}{30g/mol}=400mol$

The chemical reaction for hydrogenation of ethene follows the equation:

$C_2H_4+H_2\rightarrow C_2H_6$

By Stoichiometry of the reaction:

When 1 mole of ethane releases 140 kJ of heat.

So, 400 moles of ethane will release = $\frac{140}{1}\times 400=56000kJ$ of heat.

Converting this into Mega joules, using the conversion factor:

1 MJ = 1000 kJ

So, $\Rightarrow 56000kJ\times (\frac{1MJ}{1000kJ})=56MJ$

Hence, the amount of heat released is 56 MJ.

8 0

3 years ago

You are on an alien planet where the names for substances and the units of measures are very unfamiliar. Nonetheless, you obtain

Margarita [4]

Answer: 12

Explanation.

This problem was recently posted and deals with the conversion of units,so I give the same answer.

You need to convert the 9 quibs of skvarnick to sleps, to determine how many sleps you have.

The conversion of units is easily undertaken once you build your conversion factors.

Conversion factors are ratios (fractions) equivalent to one, which permits use the identity property of the multiplication to change one unit to a different equivalent one.

Remember that the identity property of multiplication states that any amount multiplied by 1 remains unchanged, i.e.

$a.1=a$

Then, build your conversion factor from the definitions given:

12 sleps is equal to 9 quibs.

12 sleps = 9 quibs

in virtue of the division property of equality, you can divide both sides by 12 sleps and get:

1 = 12 sleps / 9 quibs ← conversion factor

Now you can multiply the amount 9 quibs by the conversion factor, which is equal to 1, to find the equivalent amount of sleps:

identity property: 9 quibs = 9 quibs × 1

substitution property: 9 quibs = 9 quibs × 12 sleps/ 9 quibs

You can see that the unit quibs appear in the numerator and the denominator so it cancels out, and the result will be in sleps.

So, all you have to do now is the operations with the numbers:

9 quibs = (9 × 12 / 9) sleps = 12 sleps ← answer

3 0

3 years ago