Answer:
9/16 Kinked tail, normal growth
3/16 Kinked tail, obese growth
3/16 normal tail, normal growth
1/16 normal tail, obese growth
Explanation:
Kinked tail (K) is dominant over normal tail (k) and normal growth (N) is dominant over obese growth (n). Two mice that are heterozygous for both traits (KkNn) are crossed:
KkNn x KkNn
offspring:
<em>9/16</em><em> K_N_ - Kinked tail, normal growth</em>
<em>3/16</em><em> K_nn - Kinked tail, obese growth</em>
<em>3/16</em><em> kkN_ - normal tail, normal growth</em>
<em>1/16</em><em> kknn - normal tail, obese growth</em>
(See the attached image for the Punnet's square analysis)
The conversion of DNA information into the messenger RNA is transcription. In the transcription process the genetic code sequence is transcribed into the mRNA by the enzyme RNA polymerase. Hence the process conversion DNA sequence into mRNA is called as transcription.
Answer:
They would be color blind.
Explanation:
For example, if the red cone is missing you will be unable to see colors containing red as clearly. There are several different types of color blindness. Dichromatism is when one of the cones is missing.
Answer:
1. Presynaptic cell 2. Postsynaptic cell and 3. Neurotransmitters
Explanation: Just did the assignment
Answer: Option D) 1:4
Explanation:
Recall that the sum of all nitrogenous bases in the DNA nucleotide is equal to 100%. And specific base pairings of Adenine to Thymine (A=T), and Cytosine to Guanine (C=G) must be equal.
So, the percentage of Adenine equal thymine, and that of cytosine equals guanine.
Now, A + T + C + G = 100%
So, if adenine makes up 10% of the DNA nucleotides, then thymine is also 10%.
Then, 10% + 10% + C + G = 100%
20% + C + G = 100%
C + G = 100% - 20% = 80%
Thus, divide 80% by 2 to obtain the individual percentage of cytosine and guanine. Each will take 40%
Ratio Adenine to Guanine is 10% to 40%
or 1:4 in simplest form
