Answer:
You did not post the options, but i will try to answer this in a general way.
Because we have two solutions, i know that we are talking about quadratic equations, of the form of:
0 = a*x^2 + b*x + c.
There are two easy ways to see if the solutions of this equation are real or not.
1) look at the graph, if the graph touches the x-axis, then we have real solutions (if the graph does not touch the x-axis, we have complex solutions).
2) look at the determinant.
The determinant of a quadratic equation is:
D = b^2 - 4*a*c.
if D > 0, we have two real solutions.
if D = 0, we have one real solution (or two real solutions that are equal)
if D < 0, we have two complex solutions.
The formula in solving the area of a square is Area = a² where "a" is for the length of the side. The area formula in solving a cube is Area = 6a² where "a" is for the length of its side.
Area of square = a²
64 = a²
a = 8 units
Area of cube = 6a²
64= 6a²
a = 3.27 units
The difference of side of the square and side of the cube is shown below:
Difference = 8 - 3.27
Difference = 4.73 units.
The answer is 4.73 units.
Answer:
2/16
Step-by-step explanation:
i just doubled he equation
As you bring all the non-variable numbers over to the right side, it becomes 384 which you then will divide the 32 in x which gives us 12. so x=12