Question

Factor the Quadratic: 3x^2+12x-36=0

Answer 1

Answer:

3x ^ 2 + 12x-36 = 0

3(x²+ 4x-12)=0

3(x²-2x+6x-12)=0

3[x(x-2)+6(x-2)]=0

3(x-2)(x+6)=0

⇒$\left \{ {{x-2=0} \atop {x+6=0}} \right.$⇔$\left \{ {{x=2} \atop {x=-6}} \right.$